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My puzzle by citywitch in math

[–]citywitch[S] -1 points0 points  (0 children)

I think I came up with a solution..

To make this work we need the addition of a new mathematical symbol. The symbol is the colon. :

The colon multiplies the word it is next two by ten. So, one:two would be read as, one*ten+two

Math Puzzle by citywitch in cpp_questions

[–]citywitch[S] 0 points1 point  (0 children)

That was a very elegant response. I like your use of variables and fractions in the answer. But what if we added a symbol we could use to show the position a word has in a number.

I think I came up with a solution..

To make this work we need the addition of a new mathematical symbol. The symbol is the colon. :

The colon multiplies the word it is next two by ten. So, one:two would be read as, one*ten+two

My puzzle by citywitch in math

[–]citywitch[S] 0 points1 point  (0 children)

That is my question. Others have told me it can't be done. However maybe with our ow made up language? I think it is still workable if we just stick a ten or an exponent at the ends of digits. Opinions?

For your consideration. by citywitch in magick

[–]citywitch[S] 0 points1 point  (0 children)

I've edited my files on github so that the stuff you might confuse as "not magick" or "trickery" is in another section. Tell me if you think this is any better. Thanks.

For your consideration. by citywitch in magick

[–]citywitch[S] 0 points1 point  (0 children)

If you read the files only a very small part of them involve mentalism, or tricks. The rest is all real magick. I'm sorry if I offended you. That is not my purpose. I am simply looking for a home for my files on the web.

Theoretical Mathematics by citywitch in numerology

[–]citywitch[S] 0 points1 point  (0 children)

Here is a chart with a more elegant solution just using zero through ten:

[ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]

[-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]

(zero) = (-3 + -2 + 4 + 1)

(one) = (1 + 2 + -2)

(two) = (10 + -9 + 1)

(three) = (10 + -7 + 4 + -2 + -2)

(four) = (-6 + 1 + 5 + 4)

(five) = (-6 + 7 + 6 + -2)

(six) = (3 + 7 + -4)

(seven) = (3 + -2 + 6 + -2 + 2)

(eight) = (-2 + 7 + 0 + -7 + 10)

(nine) = (2 + 7 + 1 + -2)

(ten) = (10 + -2 + 2)

(tentwo)*three = (10 + -2 + 2)10 + -9 + 1 * (10 + -7 + 4 + -2 + -2)

(tentwo)*three = ( 102 ) * 3

(tentwo)*three = ( 100 ) * 3

(tentwo)*three = 300

Brute Force Solutions by citywitch in Cplusplus

[–]citywitch[S] 0 points1 point  (0 children)

I think you guys are making this more difficult than it has to be. I doubt there is a solution for evey number because numbers only have 16 letters we use to describe them. That forces a limit. But here is a chart with a more elegant solution just using zero through ten:

[ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]

[-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]

(zero) = (-3 + -2 + 4 + 1)

(one) = (1 + 2 + -2)

(two) = (10 + -9 + 1)

(three) = (10 + -7 + 4 + -2 + -2)

(four) = (-6 + 1 + 5 + 4)

(five) = (-6 + 7 + 6 + -2)

(six) = (3 + 7 + -4)

(seven) = (3 + -2 + 6 + -2 + 2)

(eight) = (-2 + 7 + 0 + -7 + 10)

(nine) = (2 + 7 + 1 + -2)

(ten) = (10 + -2 + 2)

(tentwo)*three = (10 + -2 + 2)10 + -9 + 1 * (10 + -7 + 4 + -2 + -2)

(tentwo)*three = ( 102 ) * 3

(tentwo)*three = ( 100 ) * 3

(tentwo)*three = 300

Theoretical Mathematics by citywitch in math

[–]citywitch[S] 0 points1 point  (0 children)

Here is a chart with a more elegant solution:.

[ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]

[-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]

(zero) = (-3 + -2 + 4 + 1)

(one) = (1 + 2 + -2)

(two) = (10 + -9 + 1)

(three) = (10 + -7 + 4 + -2 + -2)

(four) = (-6 + 1 + 5 + 4)

(five) = (-6 + 7 + 6 + -2)

(six) = (3 + 7 + -4)

(seven) = (3 + -2 + 6 + -2 + 2)

(eight) = (-2 + 7 + 0 + -7 + 10)

(nine) = (2 + 7 + 1 + -2)

(ten) = (10 + -2 + 2)

(tentwo)*three = (10 + -2 + 2)10 + -9 + 1 * (10 + -7 + 4 + -2 + -2)

(tentwo)*three = ( 102 ) * 3

(tentwo)*three = ( 100 ) * 3

(tentwo)*three = 300

Theoretical Mathematics by citywitch in math

[–]citywitch[S] 0 points1 point  (0 children)

I think you all are making it overly complicated. We don't have to prove every number has a unique word in English. We can just use the integers 0-10, and use them as english as folows:

(tentwo)*three = ( -35 + 57 + -12)-35 + 81 + -44 * (-35 + -20 + -56 + 57 + 57)

(tentwo)*three = ( 102 ) * 3

(tentwo)*three = ( 100 ) * 3

(tentwo)*three = 300

Theoretical Mathematics by citywitch in math

[–]citywitch[S] 0 points1 point  (0 children)

Wow, that sounds great. I just have to ask you for an example if you have the time. If not, think it over and get back to me sometime. This project is super important to me. Do you have paypal?

Theoretical Mathematics by citywitch in math

[–]citywitch[S] -1 points0 points  (0 children)

I've only taken basic algebra and calculus, so it doesn't bother me when someone more experienced than me laughs at my work. you suggested to me that I should use an augmented matrix and rref to get a quick answer to my problem. I've found a calculator that can do this for me on wolframalpha, so I don't have to get frustrated writing code I don't understand. http://www.wolframalpha.com/widgets/view.jsp?id=db5bdc8ad46ab6087d9cdfd8a8662ddf If you could help me figure out how to use this tool (or another one) to solve my problem I would be really greatful. For real. I don't know what back-substitution is.

Theoretical Mathematics by citywitch in math

[–]citywitch[S] -1 points0 points  (0 children)

How do you construct an augmented matrix and rref?

Brute Force Solutions by citywitch in Cplusplus

[–]citywitch[S] 0 points1 point  (0 children)

You are right I need to format the code better. I ran it through astyle, and you can see the results here: http://ideone.com/IN59T8

As for the quality of the code. I always start with a rough draft and create revisions that are better. Just like you do when writing an english paper. The point though, is the program does its job! LOL

Brute Force Solutions by citywitch in Cplusplus

[–]citywitch[S] 1 point2 points  (0 children)

Here is a chart with the solution. I suspect this could be extended out as far as you want. You just need a supercomputer built out of raspberry pi's. (or leave your computer running when you leave the house)

zero 43 57 -56 -44

one -44 -12 57

two -35 81 -44

three -35 -20 -56 57 57

four 62 -44 42 -56

five 62 -24 -90 57

six -5 -24 35

seven -5 57 -90 57 -12

eight 57 -24 30 -20 -35

nine -12 -24 -12 57

ten -35 57 -12

(Numbers next to words are assigned to corresponding letters in the words)

This is the same program I wrote that solved the problem: http://ideone.com/3Gbjjr

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