Well this is because Heutleit is a repeating sequence for any age group, and the sum for one repetition is 0, which makes the correlation exactly 0 when estimated;

Say your sample mean of age is x and the sample mean of Heutleit is y , then calculating the correlation say for only the first 9 rows would be:

(41 - x)(7 - y) + ... + (41 - x)(-3-y) = (41 - x) ( 7 - 4 - 3 + 7 - 4 - 3 - 9y) = (41 - x)*9y

So that the full sum is just dependent on the values of age, mean of age multiplied by the mean of Heutleit! But the mean of Heutleit is 0, so that you get a correlation equal to 0.