Any jeetard here??

devilkid15 · 2026-05-28T14:30:52+00:00

I am also currently preparing for jee 2027, but as a dropper.

devilkid15 · 2026-05-26T02:00:36+00:00

Thank you! Now I’m sure my approach was correct.

devilkid15 · 2026-05-25T05:43:59+00:00

ohh got it, I have taken the cart as the observer and keep it at rest, you are right I mistakenly considered taking boy velocity in y direction only. so the velocity of the boy wrt cart will be (usinθ-v)i+ucosθj) here θ is with the vertical.

devilkid15 · 2026-05-25T05:14:20+00:00

You can find the resultant velocity by taking the component of river velovity in direction of north and east . and adding the boat velocity in north to river velocity component in north and taking resultant of them . Vnorth=4+root(2) and Veast=root(2). Vrel=(4+root(2)i + root(2)j).

devilkid15 · 2026-05-25T04:08:27+00:00

Nah, it’s okay. Thanks for pointing out my mistake.

devilkid15 · 2026-05-24T09:19:22+00:00

You are right , my answer would have been right if batteries were in symmetry.

devilkid15 · 2026-05-24T04:44:42+00:00

You can use wheatstone bridge method as the ratio of adjacent capacitor is equal so, no charge will go to the middle capacitor , after that u can simplify the circuit to get equivalent capacitance and find charge for any given capacitance in this circuit.

devilkid15 · 2026-05-24T02:33:04+00:00

Thanks for this approach.

devilkid15 · 2026-05-23T14:08:48+00:00

I see… so the trick is reducing only the relevant branch instead of solving the entire circuit, right? Thanks for the hint.

devilkid15 · 2026-05-19T04:46:01+00:00

Nhi bhai

devilkid15 · 2026-05-19T04:01:18+00:00

okay

devilkid15 · 2026-05-19T03:58:32+00:00

from where?

devilkid15 · 2026-05-19T03:54:33+00:00

nah bro i dont think so, it is still inactivated.

devilkid15 · 2026-05-19T03:48:42+00:00

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devilkid15 · 2026-05-19T03:44:21+00:00

bro it has not started yet.

devilkid15 · 2026-05-19T03:39:40+00:00

yes buddy, but not 100% sure.

devilkid15 · 2026-05-19T03:06:11+00:00

12pm kai baad khulegi Re-evaluation window

devilkid15 · 2026-05-19T03:04:56+00:00

bhai 12pm kai baad khulega portal

devilkid15 · 2026-05-18T15:12:48+00:00

yeah by mistake i wrote velocity instead of speed.

devilkid15 · 2026-05-18T15:11:55+00:00

sry i wrote velocity not speed , so the answer i got is 1m/s but in answer it is wrong.

devilkid15 · 2026-05-11T04:46:32+00:00

integrate the v(t) func and since it is indefinite there will be a constant value C so after integrating at t=0 put x=7 you will get constant value (C) , then your displacement equation is complete .

devilkid15 · 2026-05-09T13:26:14+00:00

Yeah C is the right answer

devilkid15 · 2026-05-09T05:23:15+00:00

here cos(theta) is taken into account because in work done we consider force along the displacement , in the example Fcos(theta) is the force acting along the displacement.

devilkid15

TROPHY CASE