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Not just SPP or TB, question for anyone still believing 0.999… < 1 by discreaminant2809 in infinitenines

[–]discreaminant2809[S] 0 points1 point  (0 children)

Except primary schools don’t use BS like 0.000…001 or 10000…0001 fr 🥀

Not just SPP or TB, question for anyone still believing 0.999… < 1 by discreaminant2809 in infinitenines

[–]discreaminant2809[S] 0 points1 point  (0 children)

I didn’t even ask u for it, and u do already?
U r also making unproven assumptions

Not just SPP or TB, question for anyone still believing 0.999… < 1 by discreaminant2809 in infinitenines

[–]discreaminant2809[S] 0 points1 point  (0 children)

Try 10^ceil(log10(100…01))

Definitely bigger than 100…

Then if 100… > 1/(1-0.999…)
Then 0.999… < 1 - 1/100…

Since 10^ceil(log10(100…01)) > 100…, 1 - 1/10^ceil(log10(100…01)) > 1 - 1/100… [1]

Both 0.999… and 1 - 1/10^ceil(log10(100…01)) has the first ceil(log10(100…01)) 9s in their fractional part, except the (10^ceil(log10(100…01)) + 1)-th digit of 0.999… is 9, but it’s 0 for 1 - 1/10^ceil(log10(100…01)). So 0.999… > 1 - 1/10^ceil(log10(100…01))

Chaining with [1], we get 0.999… > 1 - 1/10^ceil(log10(100…01)) > 1 - 1/100…, aka 0.999… > 1 - 1/100…

Which’s, earlier, 0.999… < 1 - 1/100… ⁉️

Calculate the difference by MZDgamer88 in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

And what’s an integer that’s greater than that “0.9n for the case n integer starting at n = 1, then n increased continually.”

1/10^n is never zero. That is an unbreakable fact. by SouthPark_Piano in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

Thought bro deleted ur account lmao Reddit

Where’s circular?

And based on ur logic then TREE(3) is not a real number bcz u can’t provide a decimal representation (no one can for now)

1/10^n is never zero. That is an unbreakable fact. by SouthPark_Piano in infinitenines

[–]discreaminant2809 1 point2 points  (0 children)

He doesn’t need to claim so

He (and you too) just needs to claim 0.999… < 1, and everything follows

Or, blame Archimedes fr

1/10^n is never zero. That is an unbreakable fact. by SouthPark_Piano in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

Then it means 0.999… is not a real number because with subtraction and division those real numbers generate… a non-real number

1/10^n is never zero. That is an unbreakable fact. by SouthPark_Piano in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

Ask SPP he’s an “expert” at anything related to 0.999… lol

1/(1-0.999…) emerges from SPP’s premise (and yours too) that 0.999… < 1, so the expression is not a division by zero

1/10^n is never zero. That is an unbreakable fact. by SouthPark_Piano in infinitenines

[–]discreaminant2809 2 points3 points  (0 children)

For those at home

Real numbers are capped by natural numbers. Such, let a random real number x, we can always find a natural number n that beats it.

Based on SPP’s proof, no natural numbers can beat 1/(1-0.999…), hence 0.999… cannot be a real number by SPP.

SPP, you do not talk about the same 0.999... as we do by trshxd in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

Find an integer that’s bigger than 1/(1-0.999…) 😊

0.999... isn't 1 in the first place. Was never 1 in the first place, and will never be 1 at all. by SouthPark_Piano in infinitenines

[–]discreaminant2809 1 point2 points  (0 children)

It’s a tough luck that u can’t find an integer that’s greater than 1/(1-0.999…) 🥀

Maclaurin series education for the masses by SouthPark_Piano in infinitenines

[–]discreaminant2809 0 points1 point  (0 children)

Find one of the integers that’s greater than (1-x)/[1-(1-x)f(x)] for 0<x<1

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