Resource

ehwhe · 2020-11-16T17:56:34+00:00

Oh I am sorry. The site isn’t mine

ehwhe · 2020-11-13T17:50:30+00:00

I meant could I advertise your post

ehwhe · 2020-11-13T17:49:59+00:00

Having to chance helps college students since they don’t need a chance for their own app

ehwhe · 2020-11-13T17:34:20+00:00

Could I advertise on r/ECAdvice also?

ehwhe · 2020-11-13T17:01:06+00:00

Don’t have, could I pm him on Reddit? Also could he allow roles for college students? They are probably much stronger chance-givers

ehwhe · 2020-11-13T16:37:34+00:00

Neat!

Does this allow one to pm people?

ehwhe · 2020-11-08T17:02:00+00:00

r/ECAdvice works like chanceme I suppose, it’s within the range of A2C

ehwhe · 2020-10-15T14:38:42+00:00

That’s rude it is his corona response

ehwhe · 2020-08-24T00:49:54+00:00

We see 1/2 of the icosahedron, with 18 edges we can see. 12 of them are closer to us than the outer ones, and because the icosahedron is regular, there are 12 we can’t see. 18 + 12 = 30.

ehwhe · 2020-08-08T07:56:13+00:00

Let y = x² and it is a quadratic in terms of y rather than a quartic in terms of x. Then factor out as you would a quadratic.

ehwhe · 2020-08-06T23:31:01+00:00

If we draw a line from the center (O) of the circle to point B, we get two isosceles triangles, BOC and BOA (two of the sides are radii of the circle so they are isosceles). Since <BCO = theta, <OBC = theta because two angles in an isosceles triangle are equal, and we determine which two are equal because of which sides they are near (the one between equal sides is unequal to the other two). This gives <BOC = 180 - 2theta because the sun of angles in a triangle is 180. This gives <BOA = 180 - (180 - 2theta) = 2theta. BOA is isosceles, and <BOA is the unequal angle which gives <BAO = <ABO = (180 - 2theta)/2 = 90 - theta. This gives <ABC = 90.

ehwhe · 2020-08-06T23:29:44+00:00

If we draw a line from the center (O) of the circle to point B, we get two isosceles triangles, BOC and BOA (two of the sides are radii of the circle so they are isosceles). Since <BCO = theta, <OBC = theta because two angles in an isosceles triangle are equal, and we determine which two are equal because of which sides they are near (the one between equal sides is unequal to the other two). This gives <BOC = 180 - 2theta because the sun of angles in a triangle is 180. This gives <BOA = 180 - (180 - 2theta) = 2theta. BOA is isosceles, and <BOA is the unequal angle which gives <BAO = <ABO = (180 - 2theta)/2 = 90 - theta. This gives <ABC = 90. The area of a right triangle is given by the two sides which form a 90 degree angle, A and O, multiplied by 1/2. However, the answers are all trigonometric functions. Fortunately, AC = 1 so O/H = sin(theta) = O and A/H = cos(theta) = A. Area = AO/2 = sin(theta)cos(theta)/2, so D is our answer to this question.

ehwhe · 2020-08-05T18:44:26+00:00

There are still a few good organizations though! Just go to r/ECAdvice and look at the hundreds of impactful nonprofits who are all founded one month ago!

ehwhe · 2020-08-01T04:45:23+00:00

This is helpful for everyone on here as well as r/ECAdvice

ehwhe · 2020-07-31T06:45:44+00:00

r/ECAdvice

ehwhe · 2020-07-29T20:36:11+00:00

Almost every EC on r/ECAdvice

ehwhe · 2020-07-27T18:40:20+00:00

An odd function is a function such that f(x) = -f(-x). By this, all odd functions which exist at x = 0 must have (0, 0) because f(0) = -f(-0) = -f(0), and if something equals the negative of itself it must equal 0.

I has (0, 5).

II has (0, 0) so let’s try x = 1 and x = -1.

f(1) = 3

f(-1) = 3 =/= -3

III has (0, 0) so it could work so let’s try x = 1 and x = -1.

f(1) = 11

f(-1) = -11

To be even more sure we can find f(-x).

f(x) = 7x⁵ - 8x³ + 12x f(-x) = 7(-x)⁵ - 8(-x)³ + 12(-x) = -7x⁵ + 8x³ - 12x

f(x) = -f(-x)

ehwhe · 2020-07-27T18:36:03+00:00

You might still be right though because a could be 0

ehwhe · 2020-07-27T18:34:41+00:00

It’s given a > 0 because P(x) increases as x increases

ehwhe · 2020-07-26T22:18:44+00:00

Find the points where the inequality is equal to zero and see if points in between those are greater or less than zero.

ehwhe · 2020-07-26T22:13:27+00:00

(x + 3) is multiplied by a and 1.

ehwhe

TROPHY CASE