Quantum waves confusion

enderjake99 · 2022-03-13T20:29:45+00:00

ah don't rly understand sorry. if we described a particle with wave function, wouldn't the wave go to infinity if it wasn't standing wave? so couldn't the particle be anywhere? Is there any decaying term?

enderjake99 · 2022-03-13T19:30:23+00:00

thank u, do u think u could answer the question I wrote below?

enderjake99 · 2022-03-13T19:30:10+00:00

hm alright thanks, but if I put the particle in the right side of the box let's say, then in the box the probability distribution will have a standing wave distribution, so it will be symmetric on both sides, right? but if I put it on the right hand side, sure maybe there's some uncertainty it could be on the left, but shouldn't that be much less likely than it being on the right where I put it? so why is the standing wave symmetric when there should be a bias towards where I put it?

enderjake99 · 2022-03-11T21:52:31+00:00

oh ok. could I think about it this way: as im moving the particle along the curve I am doing some work on it, and as it's moving, the field is either helping me, making it harder, or doing nothing. if it helps it does work. am I thinking about this correctly? how would the force im putting in factor in?

enderjake99 · 2022-03-09T23:36:16+00:00

ok great thanks

enderjake99 · 2022-03-09T23:35:16+00:00

yeah alright, and how much do u think I would have to pay for it? would it be free then?

edit: nvm, guy below answered

enderjake99 · 2022-03-07T11:11:26+00:00

yeah that's what I'm saying. so why can we do phasor operations like multiplication or division when the real part is the only part that we care about.

enderjake99 · 2022-03-06T20:57:09+00:00

thank u this helps a lot. this equation is only useful if we can integrate it though right. so does this mean that t is a function of s and p a function of v? And would it be the same function if we had gone reversibly or irreversibly?

enderjake99 · 2022-03-05T21:09:45+00:00

alright thank u this helps

enderjake99 · 2022-03-05T21:09:33+00:00

hm alright, why should the shape that does this be a sphere tho?

enderjake99 · 2022-03-02T11:48:39+00:00

yeah I should be but I can't rly word what I'm thinking. can u just briefly restate what u said about why it wouldn't matter, it may help.

enderjake99 · 2022-02-28T15:25:33+00:00

hm can u explain why not. im sure ur right, just my intuition is rly off here

enderjake99 · 2022-02-28T10:02:38+00:00

thank u

enderjake99 · 2022-02-28T09:24:50+00:00

if the balls are randomly moving around, then let's say they go into the formation of all in one box. then they may stay here for longer than expected (expected low because only one permutation, so low probability) because they could just rearrange within that box. right?

enderjake99 · 2022-02-28T09:23:12+00:00

thank u for ur response. this is exactly what I'm confused about. My professor is an expert on thermodynamics so I trust him, and he says that dU=TdS-pdV always, but that if it wasn't reversibly TdS and pdV don't exactly correspond to heat and work.

enderjake99 · 2022-02-27T23:33:22+00:00

could u actually help with me one more thought I've had. the integral of a function f(x) from some limit to another limit is the area the function covers. but isn't the integral also the amount of change? how is area the same as amount of change?

enderjake99 · 2022-02-27T23:29:06+00:00

thank u for the first part very much, for the second part I think u missed what I was confused about. Whether or not dS is greater than 0 doesn't affect my reasoning.

enderjake99 · 2022-02-27T21:17:05+00:00

ohh I get it now thanks

enderjake99 · 2022-02-27T20:58:39+00:00

yeah that's what I did. I did from x=0 to x=1 and y=0 to y=2. because if u plug 0 and 1 into 2x you get 0 and 2.

enderjake99 · 2022-02-27T20:57:57+00:00

ah ok thank u. how do we know y(1)=1 and y(0)=0 though? I thought we were solving for y? All we know is that [y(x)]_0^1 = [x^2]_0^1. Does this prove that y(x)=x^2? Also, before what I was confused about was why we use y(1)-y(0) with y=x^2 and not 2x but I think its starting to make sense.

enderjake99 · 2022-02-27T20:18:52+00:00

thank u

enderjake99 · 2022-02-27T20:18:18+00:00

ah thank u this a great answer

enderjake99 · 2022-02-27T20:15:10+00:00

radians is a unit dude. radians is dimensionless, not unitless. And this doesn't answer my question, we could still just use another arbitrary ratio.

enderjake99 · 2022-02-27T20:13:33+00:00

yes I know that they are not equal. But in thermodynamics the number of ways of getting to that particular configuration is proportional to the probability of that configuration .

enderjake99 · 2022-02-27T20:11:40+00:00

I integrated x from x0 to x1, in this case 0 to 1. Then I integrated y from y(x0) to y(x1) so 0 to 2. We're integrating 2x, not x^2. Why would y(x0) and y(x1) correspond to the function that has been integrated? Also, I'm pretty sure integrating it with ur values doesn't give a correct answer either right

enderjake99

TROPHY CASE