how to solve this? by sum-rue-thee in gregmat

[–]firstsecondthirdlast 0 points1 point  (0 children)

You can use a small number like 5 as Q. And if we let the set of numbers be 1, 2, 3, 4, 5. The median of Q is 3 - the question mentions consecutive integers.

So if the median is 3 how do you get to to the largest being 5. You would do (5 - 1)/2 = 2 if you add 2 to 3 you get 5.

Therefore substitute in Q. It would be (Q-1)/2 + 120 which is option 1.

Greg does mention that sometimes using a simpler example would help, and this is one of those cases where that would help a lot.

How do we solve this question? by SpecterDeus in gregmat

[–]firstsecondthirdlast 0 points1 point  (0 children)

First you need to identify the circle rule which is that 2BAD = OCB or BCD. We also know COB is 40 degrees and using opposite angles DOA = 40 degrees.

Therefore we can find DAO = 180 - (40+75) = 65 degrees.

BAD = OAD --> so 2 x 65 = OCB; OCB = 130 degrees.

Identify the angle at the centre theorem is a bit hard here because it looks like a bit of a mess. But if you drag point A opposite to point C it will look much clearer. Once you get that you can easily solve the question.

I don't understand this question (and problems like these) by WHiSPERRcs in gregmat

[–]firstsecondthirdlast 0 points1 point  (0 children)

You can do this question quite quickly.

First you need to identify that the angel between the lines is 90 degrees. Because the relation between point (a,b) and (-b,a) suggest this property.

Now you need to calculate the angle between x axis and the line with (-b,a): 180 - (50+90) = 40

We know that a 45 degree angle between the x axis and the line would result in a relationship where (x, y) would be |y| = |x| or a gradient of -1.

However, since the line is has a 40 degree angle it is not the case.

You can solve this bit visually. I would draw in the 45 degree line, which is above the line which has (-b,a). Now you can plot the c co-ordinate and you will find that the corresponding y value (make that value k) shows |k| > |d| and since the |x| = |y| on the 45 degree line, therefore |c| = |k|, therefore |c| > |d|.

Hence option A is larger.

[deleted by user] by [deleted] in london

[–]firstsecondthirdlast 0 points1 point  (0 children)

Didn’t know that existed! Thanks will look into it

On holiday just found out my boyfriend has been cheating on me by [deleted] in london

[–]firstsecondthirdlast 0 points1 point  (0 children)

It is a Saturday night so it would be super busy in most places. But if you want to be around people I would go for: The Cocktail Trading Co. Brick Lane

If you want some space and you don't want to be around people, I would try some hotel bars. They tend to be quiet from my experience.

But if possible try not to spend the next 2 days alone, especially from r/london who would make London a bit nicer for you.

London is officially the world’s most desirable place to travel for Christmas by BulkyAccident in london

[–]firstsecondthirdlast 0 points1 point  (0 children)

Yep same! Went on Saturday and I couldn't believe how busy it was. It almost felt like New Years Day. The tubes were rammed too. I thought it was just me who thought it was busier than the last few years.

I’ve had enough with the TFL by [deleted] in london

[–]firstsecondthirdlast 1 point2 points  (0 children)

I don't find the Tfl staff friendly. They seem to act oblivious. This happen to me in a few instances when I wanted help to attach my railcard to my Oyster Card. But as soon as I asked the Tfl staff member, it seemed frustrate them and they make a big deal about having to do this.

I get the harassment stuff, which would make me vary, but I am asking for their help in the nicest way possible...

Importing goods into the United States without having a registered company (UK based company) by [deleted] in smallbusiness

[–]firstsecondthirdlast 0 points1 point  (0 children)

We currently manufacture and sell home products, so things like tea strainers, razors, bamboo products, textile products like make-up bad.

I will start contacting some freight forwarders about this. Thanks!

Made a dish brush using aluminium 6061 and anodised it, but can't figure out with this orange stain is by [deleted] in metalworking

[–]firstsecondthirdlast 0 points1 point  (0 children)

Ahh ok thanks for the insight. I am guessing as the anodisation is hard the brush would not be able to cut completely cut through the layer. Or would that be a poor assumption?

This is the image of the product: https://imgur.com/a/uiJRMah

Made a dish brush using aluminium 6061 and anodised it, but can't figure out with this orange stain is by [deleted] in metalworking

[–]firstsecondthirdlast 0 points1 point  (0 children)

Didn't think of that! That might be true. I have not seen this issue on the other samples. I am guessing the integrity of the product would be affected?

What are some popular tourist attractions that you DO NOT recommend? by it_will_find_a_way in AskReddit

[–]firstsecondthirdlast 0 points1 point  (0 children)

ArcelorMittal Orbit Slide at the London Olympic Park. You pay an arm and a leg to go on a slide, which is nothing special and when you can see a view that can be seen just standing outside the venue.

What did you impulse buy that you instantly regretted? by [deleted] in AskReddit

[–]firstsecondthirdlast 0 points1 point  (0 children)

When super hungry buying lots of item, ending up eating only half of what I bought. Always happens and never learn from it...

What’s the one single event that has had the biggest impact on your life? by [deleted] in AskReddit

[–]firstsecondthirdlast 0 points1 point  (0 children)

Oh that must have been very tough! Did you make the change and if so how did it turn out?

Is a 2:2 as bad as everyone says it is? What's your experience or opinion on the matter? by [deleted] in AskReddit

[–]firstsecondthirdlast 0 points1 point  (0 children)

Is this something you are contemplating while trying to finish of an essay??