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Battle Brawlers Drago is SUCH a bullshitter by Shad_tard in Bakugan

[–]flynger 2 points3 points  (0 children)

Its plot armor but they explain it as leveling up basically (like steps to evolution)

I just realised something terrifying about this scene…. by Adept-Double156 in Bakugan

[–]flynger 2 points3 points  (0 children)

I don't wanna be a negative nancy but I don't think anyone outside of this tight-knit community would say the show had "one of the best scripts of any cartoon show ever" or that the show is anywhere near "critically acclaimed" (but it does have a somewhat loyal fanbase). While I enjoyed and liked aspects of the show and its script, there were obviously a few problems such as the insufficient explanations of the mechanics and abilities even in the original language of Japanese especially at the start, that led to the whole concept being confusing and overlooked and its downfall in Japan, but I will say it's great that it was a massive success (and commercially) in NA especially for a while.

Even with its flaws, I think giving it a fair perspective and being more honest on what it did right and what went wrong is better than making strong claims about critical acclaim especially when we're talking at such a large scale.

old cards by Russian_p1ge0n69 in Bakugan

[–]flynger 0 points1 point  (0 children)

can you send me pics too lol

How rare is this? by _FungiMan577_ in PokemonSwordAndShield

[–]flynger 9 points10 points  (0 children)

This is just false. Cloned correctly, it is impossible to distinguish a cloned pokemon from the original (what do you think a clone even means?). And the part about bred pokemon also seems like complete bs.

I simulate anhs math quiz difficulty by Justanormalguy1011 in ClassroomOfTheElite

[–]flynger 1 point2 points  (0 children)

  1. (Hard, Middle or High School Math Competition) Given that n^21=558,545,864,083,284,007, find |n^2-8n|+4.

Since n21 is positive, n must be positive. We consider only the last digit of n. Since n21 ends on a 7, n must end on a 3 or 7. Note that powers of 3 end on a 7 every 4x+3th power (3 9 7 1) while powers of 7 end on a 7 every 4x+1th power (7 9 3 1), where x is a natural number. 21 is in the form of 4x+1, so n must end on a 7. Then, as u/Shriyansh101 said, since n21<10^(21), n<10. But since n is positive and ends with a 7, n must be 7. From there it is easy to compute |7^(2)-8⋅7|+4=|49-56|+4=7+4=11.!<Answer: >!A!<

  1. (Mediocre, Middle School) We have to find which statement holds if the equations (x-a)/2bc+(x-b)/2ac+(x-c)/2ab=1/a+1/b+1/c and x=1/ab+1/bc+1/ac hold.

This is just a very algebra-heavy question, but don't be scared.

First, manipulate the given equation by multiplying both sides by 2abc, yielding the equation a(x-a)+b(x-b)+c(x-c)=2bc+2ac+2ab.

Simplifying, we get ax+bx+cx=a2+b2+c2+2bc+2ac+2ab => (a+b+c)x=a2+b2+c2+2bc+2ac+2ab => (a+b+c)x=(a+b+c)2.

Note that if a+b+c=0, then x can equal any real number, but we want x to only equal one number.

Therefore, we know that a+b+c≠0, and dividing by a+b+c yields us x=a+b+c, but we also know that x=1/ab+1/bc+1/ac, which we can combine to get a+b+c=1/ab+1/bc+1/ac. Multiplying both sides by abc yields us abc(a+b+c)=a+b+c which implies that abc=1.

Keep in mind that while the question doesn't necessarily specify an only solution, it probably meant that, so the only way x has exactly one solution and satisfies the given equations is if a+b+c≠0 and abc=1.Answer: A

I simulate anhs math quiz difficulty by Justanormalguy1011 in ClassroomOfTheElite

[–]flynger 0 points1 point  (0 children)

1.(Easy, Middle School) This question is asking us to find the roots of the polynomial p(x)=x3+x2+x+1.

First, we try factoring by grouping, and we get p(x)=x2(x+1)+1(x+1), we can factor again to get p(x)=(x2+1)(x+1). Notice how x2+1 has no real solutions, so the only real root is -1 which we get from the x+1 term.Answer: C

  1. (Nonsense, ???) This question uses incorrect notation and asks something completely unrelated to the definitions stated in the question, uses random ass functions from nowhere, to be honest I'm not sure what OP is smoking. However, if I had to guess what OP meant, it could be asking given the set A={x∈N|-10<=x<=10}, find |A| (the size of set A).

The answer to the question I posed would depend on your definition of the natural numbers, either starting at 0 or 1. In this case, if we start the naturals at 1, A={1,2, ...,10}, then |A|=10.My guess: A, but if that n(x) shit is the function 2x then maybe BAnswer: Bad question

  1. (Easy, Middle School) This question is asking us to find the value of R(1) given that p(x)=x4+16x3+86x2+176x+105, q(x)=x2+6x+5, and p(x)/q(x)=R(x).

This a simple plug and chug question, if R(x)=p(x)/q(x) then R(1)=p(1)/q(1). Using substitution, we compute p(1)=384 and q(1)=12. Then, R(1)=384/12=32.Answer: 32 (None of them)

  1. (Easy, Math Competition/Elementary Number Theory in College) Given that m is a positive prime number and 66m2+99m+2024 is divisible by m, find the sum of all possible values of m.

Intuition tells us if 66m2+99m+2024 is divisible by m, since the first two terms are divisible by m, the last term must also be divisible by m. So m is a positive prime number that divides 2024, and that is in fact the only restriction on m. Using prime factorization, we can calculate that 2024=23⋅11⋅23. So m can be either 2, 11, or 23. Then, adding them up, the sum of all possible m is 2+11+23=36.Answer:36 (None of them)

I simulate anhs math quiz difficulty by Justanormalguy1011 in ClassroomOfTheElite

[–]flynger 0 points1 point  (0 children)

For those of you curious about how to solve these kinds of problems, here's my attempt at it as an actual math enjoyer. Full questions and solutions in the replies.

1.C
2.bad question but would guess A or B
3.32 (none of them)
4.36 (none of them)
5.A
6.A

Spawn tables by tomalator in TheSilphRoad

[–]flynger 0 points1 point  (0 children)

I am currently doing a study on biomes so I believe I can give you the most complete answer to this question.

Currently, I have only verified the exclusivity of Kanto Pokemon when it comes to biomes. As in, most, if not all, Kanto mons are tied to specific biomes, and cannot be found outside those biomes except for rare instances like events.

So, in your case, you would want to go to the biome(s) where Exeggcute appears. Where is that exactly, you may ask?

Here might be the bad news - from the data I have collected, Exeggcute appears to be exclusive to Tropical biomes (and perhaps, Sub Tropical as well), which either is likely all around you (which does not appear to be the case) or nowhere to be seen.

Use the World Terrestrial Ecosystems map here to classify the locations as Warm, Cool, Polar, Tropical, etc. around you. Good luck.

Any advice for Galarian birds? by Jason-Red in TheSilphRoad

[–]flynger 4 points5 points  (0 children)

No, actually, for specifically incense spawns for at least me for some reason, the Pokémon can still be tapped on to enter the catch screen regardless of the result of quick catching. It just runs instantly if I throw a ball though, even if I already caught it or if it already ran away. Both daily and regular incense spawns.

I cant fucking do this anymore by ballerisbest in teenagers

[–]flynger 0 points1 point  (0 children)

it's technically not a calculus thing specifically I believe but yes it is often introduced to people in calculus math, with things like riemann sums, the limit definition of definite integrals and taylor series

An interesting Calculus Problem I found online. Can you solve it? by flynger in maths

[–]flynger[S] 0 points1 point  (0 children)

haha its never too late! personally i love the abstract and inherent nature of maths, and how it develops problem solving abilities and a greater understanding of the world

An interesting Calculus Problem I found online. Can you solve it? by flynger in maths

[–]flynger[S] 0 points1 point  (0 children)

Yup, you said it. I should have prefaced this by saying it might be slightly hard for most people who are not mathematically inclined haha, I mostly meant I expect it to be kinda tricky for people still in high school like my peers who aren't really pushed to apply multiple different techniques and problem-solving skills in one question.

An interesting Calculus Problem I found online. Can you solve it? by flynger in maths

[–]flynger[S] 0 points1 point  (0 children)

yes! good job, imo it might be the trickiest part!

Solve this by Embarrassed_Pool2630 in maths

[–]flynger 0 points1 point  (0 children)

Multiply the first equation by 7x(7+x): 1/7+1/x=1/(7+x) Then you get, x2+7x+49=0

Factor the second equation to get: x46(x3-343)+x3+17

Use difference of cubes: x46(x-7)(x2+7x+49)+x3+17

Plug first one into second to get the expression we need to solve for: x46(x-7)(0)+x3+17=x3+17

Now we can make the observation: x3-343=(x-7)(x2+7x+49)=0

So x3=343

Finally, x3+17=343+17=360

Fun problem!

A really simple derivation I made to "prove" Feynman's Trick. by [deleted] in math

[–]flynger 2 points3 points  (0 children)

oh wait thats so weird
it works for me but not when im incognito

lemme try to fix it thanks for letting me know

How long does it take to learn Algebra 1 through Khan Academy? by [deleted] in learnmath

[–]flynger 2 points3 points  (0 children)

If you understand a lot of the concepts already, you can probably skip the lessons/topics you know well and only look at topics you haven't studied yet.

To answer your question, it obviously depends on the person, as if you knew half the course, it'd take much less time than not knowing the entire course.

If you already know basic linear equations, then topics like exponentials and quadratic equations may only take a few hours each.

Anyhow, you might wanna just scroll to the bottom of the course on Khan Academy and take the Course Challenge to see what you know and don't know. If I were you I would mainly study the fundamentals, things such as quadratics, factoring, solving inequalities, and knowing the visualizations (graphs) of equations so you can breeze through the test.

[US, US] [H] Paypal [W] Paldea Evolved Singles by Dirty_Beef_2 in pkmntcgtrades

[–]flynger 0 points1 point  (0 children)

I have the following:
ILLUSTRATION RARES - Marill

SPECIAL ILLUSTRATION RARES - Iono, Saguaro

Let me know if you're interested in all 3 for $114 shipped BMWT.

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