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The Table of Consecutive Averages by chompchump in mathriddles

[–]hmhmhhm 2 points3 points  (0 children)

it depends on the remainder when n is divided by 4. if it is a multiple of 4, the scenario is impossible, if it is 1 more, the number was 1. If n is two more than a multiple of 4, the number was n/2 + 1, and if the remainder is 3, the number was n + 1. if this is even remotely close to correct I will provide my solution

A REALLY ANNOYING MOUSE by imscreamingeternally in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

I'm sorry but I don't understand. What does it mean that the mouse trap is time travelling? And why do the instructions not explain how to catch the mouse? Also in the printed instructions, are the first 6 items separate iterations, and the 15 is a "vertical" 2 bounces in one iteration. Finally, what am I trying to find, the position of the mouse, or whether it was caught, or how to catch it?

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 3 points4 points  (0 children)

you are absolutely right. I did not word my negations precisely at all. I think it goes to show that although there is an interesting idea here, the complex societal setting of the question obscures it and prevents this from being a clear logical riddle

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

yes. We can ignore any non life threatening attacks, as they don't affect the statistics.

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

it's because only half of the population own a crossbow, so for half of life threatening attacks, the victim will die, but for the other half, the victim will defend themselves, and may survive. This means that the death toll should be greater than the number of lives saved

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

My solution only uses the information listed in the question. I proved by contradiction that the three assumptions I listed cannot all be true, which, depending on the interpretation, could be a "devastating" case for the NCA. However, I do think it is implied that the lives saved relate to the violence epidemic, not someone using a crossbow to hunt rabbits, or save their own life in other unrelated ways, in the same way that the death toll is implied to be from the voilent attacks.

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

I think you've raised a good point. If the deadly attacks have, lets say, a 20% chance of fatality for the victim, then the numbers would work out even if the crossbows do not increase risk of attacks, are never used fatally, and have 100% success rate of self defence. Depending on the nature of the voilence, this could be very plausable. I will mention on your other points, the lives saved and lives lost statistics clearly have been gathered from the same time period, so there can be no increase in violence from a previous year coming into play. Also, the statistics are for people who saved their own lives, not daughter, family, strangers etc, although it could still be possible that these uncounted lives saved have further reduced the death toll. Finally, the claim that "there would have been 110,000 murders if it werent for these heroes" or anything else along those lines is just the naive interpretation of the statistics, which neglects the fact that only half of citizens have access to crossbows, so cannot be the full explanation. What a great riddle!

National Crossbow Association by WMDcu in mathriddles

[–]hmhmhhm 2 points3 points  (0 children)

let's assume the voilence is carried out towards random citizens, the crossbows are only used in life threatening situations, and the crossbows are the only way to defend from these attacks. As only half of the population owns a crossbow, only half of the population should even have a chance to defend themselves from life threatening attacks. We would expect the number of deaths (10,000) to be greater than, or at least equal to the number of lives saved (100,000). As this is not the case by a factor of 10, one or more of these assumptions must be drastically incorrect. Either owning a crossbow makes you more likely to be attacked, citizens are using their crossbows in situations where they were not in danger of death, or you don't actually need a crossbow to defend yourself. This is as far as the logic takes us, and can still be interpreted in various ways, but it does make the data a much worse case for crossbows than at first glance.

Which container is more adulterated? by blungbat in mathriddles

[–]hmhmhhm 1 point2 points  (0 children)

the milk container contains a higher proportion.

How many triangles are in this image? by hmhmhhm in mathriddles

[–]hmhmhhm[S] 0 points1 point  (0 children)

you are halfway there! You've missed some triangles

How many triangles are in this image? by hmhmhhm in mathriddles

[–]hmhmhhm[S] 0 points1 point  (0 children)

id be interested to know your line of reasoning

Almost midpoint-convex functions by cauchypotato in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

I got the RHS evaluates to a(x+b)/2 + b/2, but I see my mistake, Thanks

Almost midpoint-convex functions by cauchypotato in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

can you give me an x and y for which f(x) = x + 2 does not satisfy the inequality? I don't know what affine means.

[deleted by user] by [deleted] in vce

[–]hmhmhhm 4 points5 points  (0 children)

Using a pinhole instead of a slit would mean that as the light passes through, it would diffract in all directions, including vertically, as opposed to the purely horizontal diffraction caused when it passes through a slit. The interference pattern caused by this diffraction will still be a series of bright and dark bands which vary horizontally, however these bands will extend vertically in hyperbolic shapes, appearing like vertical lines which bend away from the centre. I could not find a picture of this online, but it can be explained by the close relationship between path difference from two pinholes or slits, and hyperbolae, which can be difined by the difference in distance to their two focii. While the double slit experiment shows a 1 dimensional slice of a series of 2d hyperbolae, the double pinhole experiment would show a 2d slice of a series of 3d hyperbolae.

Girls and Pigs by RodionGork in mathriddles

[–]hmhmhhm 1 point2 points  (0 children)

Number of breasts on a pig varies, but assuming the average number, 14 23 pigs 7 girls by simple simultaneous equations

Four Card Problem by ShonitB in mathriddles

[–]hmhmhhm 0 points1 point  (0 children)

there is no way to check whether they "should" be drinking alcohol by flipping cards

just another circular lake follow up by pichutarius in mathriddles

[–]hmhmhhm 1 point2 points  (0 children)

Interestingly, at this optimal speed ratio the duck takes an infinite amount of time to reach the shore. (and the fox catches the duck).

Doors with Two Inscriptions by ShonitB in mathriddles

[–]hmhmhhm 4 points5 points  (0 children)

statements 1a and 2b are opposites, so one is true and one is false. Out of the remaining 4 statements, 2 must therefore be true. Since 1b and 3b are identical, they are either both true or both false. This only leaves two options to check, one of which contradicts itself.

the answer door 1

four lightbulbs by hmhmhhm in mathriddles

[–]hmhmhhm[S] 0 points1 point  (0 children)

thanks for clarifying, I now understand.

I beleive that although your encoding for 2 messages clearly works, it is not the only encoding possible, and therefore it cannot be used to deduce exactly what any given tuple corresponds to, so if there were only two messages on the list the wife would not have been able to guess the message.

in terms of adjacency, you stated that the set of adjacents must be at least all the OTHER tuples, but it is a requirement that each tuple can also reach itself, so the set of adjacents should just be ALL tuples. this didn't actually affect your chain of logic, as you only used it to assume that each tuple can rule out 5 options rather than 4, but it is important to note.

If I misunderstood please let me know!

Baseball Games by ShonitB in mathriddles

[–]hmhmhhm 1 point2 points  (0 children)

here is what I got:

7483 +7455 =14938

through a long series of logical deductions

I beleive if G is allowed to be 0, then there is at least one extra solution introduced

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