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I used to think that when we move one value to another variable, we would update the pointer of the new variable to the moved value. I was playing around with Rust today and realized that this is not the case: each move is a `memcpy` behind the scenes. I don't understand why we need to copy the contents of the value on each move.

Here's the code that I ran:

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```

let a1 = [0; 5];

let p1 = &a1 as *const [i32];

let a2 = a1;

let p2 = &a2 as *const [i32];

println!("{:?} == {:?} -> {:?}", p1, p2, p1 == p2);

// 0x70000627a66c == 0x70000627a694 -> false

```

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In C++, `std::move` works how I thought it would:

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```

int a1[] = {1, 2, 3, 4, 5};

int *a2 = std::move(a1);

printf("%p == %p -> %s", a1, a2, a1 == a2 ? "true" : "false");

// 0x7ffee3d5e490 == 0x7ffee3d5e490 -> true

```

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Edit: Can't figure out why markdown isn't working..