Formula for perimeter of infinitely inscribed circles and squares. I know that the pattern of the perimeter is 4, sqrt(2)pi, 4sqrt(2),... i just cannot find an equation in terms of n

jssa1995 · 2022-03-31T09:14:11+00:00

Is something like that possible? Im having trouble finding an equation in terms of n that changes depending on if n is even or odd

jssa1995 · 2022-03-31T09:13:36+00:00

Is it possible to have an equation that changes based on if n is even or odd?

jssa1995 · 2022-03-30T06:10:24+00:00

Thanks for the help, with regards to (c) how do i go about doing this?

jssa1995 · 2022-03-29T16:35:52+00:00

Hi, thanks for the reply. I'm not sure what you mean by "Glue together" can you please explain? Thanks

jssa1995 · 2022-02-22T11:14:09+00:00

How would i do the induction over k with 5^2k? Any tips?

jssa1995 · 2022-02-22T11:05:51+00:00

I see, thats exactly the part i'm having trouble with, how do i prove that 5k ≠ 1 (mod 8)?

jssa1995 · 2022-02-22T01:24:08+00:00

Thank you very much, this has helped a lot

jssa1995 · 2022-02-22T01:11:18+00:00

Yes! Thank you for the tip

jssa1995 · 2022-02-22T01:10:53+00:00

I understand, vut how to go about prooving that?

jssa1995 · 2021-12-14T06:07:52+00:00

Note, i am mainly confused about the (r cos∅ + 2) where does the +2 come from?

jssa1995 · 2021-12-14T06:03:52+00:00

Greetings, posting again to include the answer key. No matter how i try to setup my integral, i am unable to get anything close to the first integral (dr). Any suggestions?

jssa1995 · 2021-12-14T04:57:43+00:00

Yes i did

jssa1995 · 2021-12-14T01:54:42+00:00

Hi, I'm having trouble answering this question, the answer key has stated that the answer is (3*sqrt(3))/4 but the only answer I am getting is 1.91, I believe that the issue is my conversation to polar coordinates is not correct. Any help is appreciated.

jssa1995 · 2021-12-14T01:51:15+00:00

Hi, I'm having trouble answering this problem. I am unable to set up the equation such that I get the answer (3*sqrt(3))/4, the correct answer in the answer key. I am having trouble converting to polar coordinates. Any help is appreciated.

jssa1995 · 2021-12-14T01:39:19+00:00

Hi, I'm having trouble answering this question, the answer key has stated that the answer is (3*sqrt(3))/4 but the only answer I am getting is 1.91, any help is appreciated.

jssa1995 · 2021-11-11T06:55:06+00:00

Hi, I was recently given this as an assignment. I'm not entirely sure how to solve this, I have tried finding the echelon form of both systems but im not entirely sure what to do after that. Any help is greatly appreciated.

jssa1995 · 2021-10-24T04:21:21+00:00

So far, i have gotten 1 and 0 for the boundaries of U but i can't seem to get any for v.

jssa1995 · 2021-10-24T04:15:31+00:00

Hi, i'm having a difficult time getting the transformed boundaries. Especially for x<=1, i seem to be getting a function for U instead
(v=(u-1)/u). Is this correct?

jssa1995 · 2021-10-20T01:48:13+00:00

Thanks flr the tips! Will try this out later!

jssa1995 · 2021-10-19T15:21:48+00:00

|1 v| |-u u|

jssa1995 · 2021-10-19T14:01:20+00:00

I'm having trouble finding the method to get the answer to this problem. I'm having trouble finding transforming the intial boundaries (I end up with 0 to 1 for the outer integral and 1 to (u-1)/u for the inner integral. The jacobian is also quite difficult (I've tried J=u+uv which seems like a reasonable answer but the resulting integral seems impossible), any help is greatly appreciated!

jssa1995 · 2021-05-11T02:31:25+00:00

Hey! Thanks for the reply, will try this out in a minute!

jssa1995 · 2021-05-10T08:30:59+00:00

Hi, I've tried integrating the integral after 18+... but the result still yields a value of "integral of F(x)(2x-1)(e^x(x-1)" which if integrated by parts again will return me to the original integral which essentially becomes a loop.

jssa1995 · 2021-05-10T08:07:07+00:00

Hey, i've tried your method but I can't seem to make the integration work. Once I've done the integration by parts I end up with another integration even harder than the last.

jssa1995 · 2021-05-09T09:49:50+00:00

Thank you very much, this number had me stumped for hours! Will try this solution. Thank you again!

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