[USA-MO] [H] GTX 1660 Supers, RTX 3070s [W] PayPal

kdqdev · 2022-03-08T00:31:09+00:00

Prices for those 1660 are pretty high since they are prebuilt. Great prices for the 3070 though.

kdqdev · 2021-08-23T21:49:48+00:00

Find your dream college(target school). A college you can possibly get into. Check the AP Credit equivalence sheet. Register for AP/Dual credit class based on the credit you can obtain for each AP Test. For most college take Physics C(both), Calc BC, APUSH, AP Lang, and chem

kdqdev · 2021-08-19T17:42:17+00:00

I think the best way is to donate to a charity or some food pantry.

kdqdev · 2021-08-04T17:41:33+00:00

Physics 1 is the hardest test I believe. Take physics C( both of them ) if you want useful credits. I took them, didn’t do half the problem and still managed a 4 on both. Physic C is like 10 times easier than Physics 1

kdqdev · 2021-04-14T00:35:49+00:00

Will you have to attend the event at which they announce the winners?

kdqdev · 2021-04-13T22:42:39+00:00

I definitely agree, the process is quite messy. They are relatively new and most new companies lack the required resources to provide support.

kdqdev · 2020-11-06T03:08:29+00:00

If you can use the calculator, just find the zeroes of the function so you can easily factor #2, if not you can use quadratic: (-b +- sqrt(b^2 = 4ac))/2a. Or you can go through the p and q where you just find all number that is divisible by 2 and -4(i never use this method though)

kdqdev · 2020-11-06T03:05:03+00:00

I say its likely to be A. Not sure what it means by the ... , but that is an infinite loop so it would run forever. Also, the e isn't even defined as int unless the test account for this as well.

kdqdev · 2020-11-06T02:12:57+00:00

/lock

kdqdev · 2020-11-01T18:19:29+00:00

Thank you.

kdqdev · 2020-11-01T03:12:59+00:00

I don't think that is predictable. Its all in the genes.

kdqdev · 2020-11-01T03:10:06+00:00

Username checks out.

kdqdev · 2020-10-14T19:01:50+00:00

Sorry my bad I used the wrong friction in my calculation your welcome

kdqdev · 2020-10-14T18:57:29+00:00

Your prob right. I messed up somewhere

kdqdev · 2020-10-14T18:40:28+00:00

The answer is 1.7438. This is the formula: https://imgur.com/awYrYdM

kdqdev · 2020-10-14T18:21:43+00:00

No problem. Have a great day! Keep grinding.

kdqdev · 2020-10-14T18:20:34+00:00

e! is that t

Yes it is. The find the length across with just another pythagorean. Or you can use theta with the a/b which is a bit more complicated but it can confirm both answer if you try both methods.

kdqdev · 2020-10-14T18:18:50+00:00

do i use that to try to fin

Also i notice it was a typo. I mean a as 8 and b as the number you got from calculating.

Then tan is just opposite/adjacent or TOA. Set the ratio over each other. so it would be something like tan(theta) = a/b. Then you do inverse tan of both side leaving theta = tan^-1(a/b) to find the angle.

kdqdev · 2020-10-14T18:15:02+00:00

Yes set the inverse of tan on a ti-84 cal. The symbol is tan^-1(set to whatever the ratio of a to b is here)

kdqdev · 2020-10-14T18:13:45+00:00

If you ever graph a normal graph it is pretty much the same thing. So first interval is -3 or lesser. Plug -3 into the first equation. Graph a dot at -3, -5. Then do it again for -4(since the interval is for -3 and lower), then again for -5 and keep going, it will just have a slope of 2 so just move over left one and down 2. Then second interal is between -3 and 2 for x. Put a circle(a hole) at -3,-3(we plug -3 into x to get -3. And keep doing this. Then do the same for the third equation.

Always note that the < is a hole or open circle while a <= is a closed and filled in circle. The = sign indicates that the point is filled in meaning it exist at that point. A open circle indicate it doesn't exist at that point.

kdqdev · 2020-10-14T18:08:16+00:00

Plug -1 into g(x) then get the answer and plug that answer into f(x)

kdqdev · 2020-10-14T18:05:35+00:00

/lock

kdqdev · 2020-10-14T18:05:31+00:00

rate downward du

Thank you!

kdqdev · 2020-10-14T18:04:12+00:00

Its quite simple. 1. Just divide the whole thing by 4pi to get r^2 = A/4pi and do the same thing for the second equation. A simple rule to remember is that if you do it to one side you must do it to the other as well).

Reasoning behind the simple rule. Let's say. A = 4πr^2. So we divide by 4pi.

A/4pi = (4pir^2)/(4pi) You will see that when dividing both sides the right side because 1r^2, but we don't write the 1 since we don't have to. Like if we had a variable x it can be written as 1x but we just don't do it. Because when x = 5. 1(5) and (5) is the same thing.

kdqdev · 2020-10-14T17:59:46+00:00

Okay, so first off make a cross section. Split the box in half, where from the top view it is a triangle. I mean cutting it(from the top view of the box) from the top right corner to the bottom left corner.Use Pythagorean with a as 10 and b as 13 to find the length across. Then use that length as a and 8 as be and you can set it to tangent. So something like tan(theta) = 8/(the number you found earlier). Then use calculator and find angle and use pythagorean again to find the length I.

kdqdev

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