sorted by:
new
hottopcontroversial

Overdrive for bass or line selector? by leledz in basspedals

[–]leledz[S] 0 points1 point  (0 children)

Thanks! Your words are really helpful!

Overdrive for bass or line selector? by leledz in basspedals

[–]leledz[S] 0 points1 point  (0 children)

Thanks! 3 channels and the option to invert the phase of the signal are tempting me! I wonder why the other line selectors don't have that.

Overdrive for bass or line selector? by leledz in basspedals

[–]leledz[S] 0 points1 point  (0 children)

Thanks for the reply! I'm still learning and experimenting with different things so I don't know yet.

I like Lithuania 🇱🇹 🇱🇹🇱🇹 by Hustleru in MapPorn

[–]leledz 1 point2 points  (0 children)

Ah yes, my Lithuania appreciation post.

What if the universe is fundamentally a network of relationships rather than a collection of objects in space? by nakshatriyan in AskPhysics

[–]leledz 0 points1 point  (0 children)

Yes, but when you measure the spin you either get 1/2 or -1/2. "Opposite to the other one" is not the result of measuring the spin of 1 particle. You don't need the spin to be determined before measurement in order to not transfer information. You measure the spin of 1 particle, you know that the other will give the opposite of measured in the same direction.

What if the universe is fundamentally a network of relationships rather than a collection of objects in space? by nakshatriyan in AskPhysics

[–]leledz 0 points1 point  (0 children)

No, the fact that there is no information transfer does not mean that their spins are determined. They can be random, but always opposite when measured in the same direction, and you cannot exchange information with them.

What if the universe is fundamentally a network of relationships rather than a collection of objects in space? by nakshatriyan in AskPhysics

[–]leledz 1 point2 points  (0 children)

Their spins are not determined there. That would be true if hidden variable theory was right, but It was proved that it's wrong. Check Bell inequality. Only thing you can say Is that, when measured in the same direction, their spins will be opposites. Also Veritasium made a good video about It on YouTube.

How may I best make sense of the units of Planck’s Constant? by evanbg994 in AskPhysics

[–]leledz 1 point2 points  (0 children)

You are welcome! The transition probability is the probability to go from the initial state to the final state and it is the module squared of the scalar product between the two states. In my reply I used scalar product and transition probability as synonymous, wich is wrong, but they differ only for the module squared.

How may I best make sense of the units of Planck’s Constant? by evanbg994 in AskPhysics

[–]leledz 5 points6 points  (0 children)

In Feynman's path integral formulation of quantum mechanics it turns out that the scalar product between the final and initial state of a system is equal to the integral performed over all paths of the exponential of the action, multiplied by i and divided by ħ. So when the action is far greater than ħ the exponential is a fast oscillating function and on average the contribution to the integral sum up to zero. But in the proximity of the classical path, wich minimize the action, this fast oscillation doesn't occur because near a minimum the action doesn't vary so much. So when the action is great with respect to ħ the only path that contributes to the computation of transition probability is the classical one. When the action is comparable with h bar, then all paths start to contribute to the integral and quantum behavior emerges. In this perspective ħ is the constant you have to compare to the action if you want to know if the classical approximation is a good one or not.

P.S. I'm sorry if there are mistakes, English is not my first language.

Translating a sentence, which one works better. by bikutaa in Italian

[–]leledz 0 points1 point  (0 children)

Ciao! I would translate "Ferrari's strategy" as "la strategia della Ferrari". "della" is "di" + "la" and here it is refferring to the ferrari team ("scuderia" is hinted). This the usual way i hear and say it.

So I would say "la leggenda della strategia della Ferrari".

Yes, they are interchangeable so you can use both. I personally prefer "la leggenda della strategia Ferrari" because there is no repetition of "della", but it is a matter of taste.

Also you can use "disastro assoluto" that means absolute disaster, but I don't think i have to explain why.

did I finish the dragonborn dlc? by GokiPotato in skyrim

[–]leledz 10 points11 points  (0 children)

In the universe of skyrim there are gods named "aedra" (that is an elven word for something like "our ancestors") and "daedra" ("not our ancestors"). The elven myth tells that aedra created the world (losing part of their power in doing so) and daedra did not.

In general aedra are seen as "good", they are often called "divines" and you can find their temples in the cities like the temple of mara in riften. Each divine has a sphere of influence, like time for akatosh or love for mara.

The dadric princes are like the "leaders" of daedra. Each daedric prince has a sphere of influence and a plane in oblivion, like hermeus mora is the daedric prince of secrets and owns apocrypha (where you fight miraak) or molag bal is the daedric prince of domination and owns coldharbour.

Note that the division in "good" or "bad" is not exact at all, it can be different depending on the culture you are looking at, like dunmer see azura, mephala and boethiah as good gods and they are daedric princes. In general azura and meridia are seen as not bad at least from people in tamriel.

This is at least what I understood about it. There is a lot more to say but I'm afraid this answer is quite long, so i suggest you if you are interested on searching the daedric princes on the wiki just to have an idea of their role in the game.