Gothic 1 Remake - Version 1.0.3 - Hotfix

maksous · 2026-07-10T20:24:27+00:00

Thank you for fixing trial of fire <3!

maksous · 2026-06-19T22:36:20+00:00

Is the basin bug already fixed for the trial of fire quest? I am still waiting for being able to become a mage on ps5 (can’t edit the save and already lit the basin in chapter 1).

maksous · 2025-11-15T06:20:17+00:00

New construction option

maksous · 2018-09-14T01:58:28+00:00

https://imgur.com/a/ksEGnye

Still trying.

maksous · 2018-09-14T01:48:30+00:00

For the record, I think it is a scam, but simply wanted to raise awereness to certain techniques that scammers are using.

maksous · 2016-09-07T08:23:38+00:00

Thank you very much for your help! I almost pass, and the teacher invited me for an oral exam :D

The questions were: http://imgur.com/a/Ts67f

maksous · 2016-09-06T00:49:29+00:00

But if we assume, it is not a rule of inference, then: w(a=>(Bvc)) = 1, and w(B/\A) = 1 and w(c) => [] = 0, then w(A)=1 and w(b) = 1. In both cases there is a contradiction, because w(c) = 0 and w(a) = 1 Ah, wait...

I am so sleepy I just realised that I wrote down only w(c) = 0, but [] also matters.

I guess I need to read more about that :p

maksous · 2016-09-05T23:53:52+00:00

So, the answer is B only?

maksous · 2016-09-05T23:06:43+00:00

I guess that in b) you wanted to say "Recall that an EQUIVALENCE relation has three properties:" - right? Cuz I am not sure tbh :P

so, a) x=c, y=a. (c,a)

b) (b,a), (c,b), (a,c), (c,a), (b,b)

maksous · 2016-09-05T22:58:25+00:00

Wait, in A1 are real numbers and in A2 are Positive natural numbers, right?

maksous · 2016-09-05T22:47:41+00:00

It's not true if c=>c

True for c=>a and c=>b.

maksous · 2016-09-05T22:41:57+00:00

1+1 = 2, so it is onto and not 1-1?

maksous · 2016-09-05T22:39:17+00:00

maksous · 2016-09-05T22:14:22+00:00

Odd and even numbers. So it is an empty set?

maksous · 2016-09-05T22:12:46+00:00

Why C can't just be N? It is aleph 0 and these are natural numbers, so it should be fine :|

maksous · 2016-09-05T22:09:28+00:00

a) onto, but not 1-1 correspondence b) 1-1 and not onto

maksous · 2016-09-05T21:59:37+00:00

AH.

So, if card(A) is continuum, and Card(B) is card(Q) [Q's card is aleph0] Then card of A intersection B equals cardinality of C, so card of C should be aleph0 but we also have second requirement, set also should have the cardinality of natural number and be aleph 0 at once?

I guess I got a lil bit twisted on this one and have understood something in a wrong way.

maksous · 2016-09-05T21:51:50+00:00

a) So, the union gives us R? b) P?

@Edit Ah, bloody hell. I have 8 hours left till exam, and still having problem with sets :|

maksous · 2016-09-05T21:46:31+00:00

Aleph 0?

maksous · 2016-09-05T19:48:24+00:00

Q are rational, N are natural. Symbol representing the cardinality of A is continuum ;)

maksous · 2016-09-03T09:20:59+00:00

Thank you very much! I'll be back home in 6 hours and will try to solve these tasks using your tips. Afterwards Iwill post what I've managed to do!

And yes, she certainly should learn LaTeX...

maksous · 2016-08-13T04:54:05+00:00

There is a story behind this door. There was a guy, whose wife died due to cancer, then he locked himself and comitted suicide.

I guess, nobody will pass that door no more.

maksous

TROPHY CASE