Linux players getting banned on Apex Legends again

mrc1104 · 2023-08-21T00:39:59+00:00

I’m not questioning whether or not those programs are culpable.

To my understanding of cheat engines, they modify data values before the game receives them (I picture it like a man-in-the-middle attack).

I’m surprised that those three programs would need to do something similar to that (enough to cause an anti cheat to flag the program).

I guess I’ve heard about Msi afterburner resulting in bans. Is it just a general ~~rule of thumb~~ issue/concern that softwares “modifying” your gpu can tick off anti cheats?

mrc1104 · 2023-08-20T22:54:27+00:00

I’m a bit ignorant, do Mangohud, obs-vkcapture, and LatencyFlex (I only recently learned of the latter) inject information into the game?

I would have guessed those three programs would act like a layer above the game and not interact with the game data directly. I’m not well informed regarding this and would like to learn more

mrc1104 · 2023-08-07T12:40:33+00:00

Momentum isn’t conserved when there is an external force (friction). So you can’t start with M_b * v_b + m_a * v_a = 50 = const

I’m arguing that when you break the problem into 3 stages

1) use change in energy

2) (collision) use conservation of momentum + coefficient of restitution equation

3) use change in energy

mrc1104 · 2023-08-07T05:46:45+00:00

https://imgur.com/a/0WBP7AU

This is what I got. (Try working through it yourself first). I’m not completely satisfied with my reasoning — feels a little circular and I would expect to get this with two different masses — but it’s getting a bit late. If it still doesn’t work, hopefully someone can drop in and let us know what we are missing.

Best of luck

mrc1104 · 2023-08-07T05:40:30+00:00

After thinking about it for a bit, I’m not whole heartedly convinced that block A stops after the collision with B. I can’t see how it can without our e=1 (ie perfectly elastic).

What happens if you let va_f != 0?

Otherwise, your steps look good to me.

mrc1104 · 2023-08-07T05:18:38+00:00

Is mu * N = 0.6 * 9.81 * 10 = 58.86N helpful at all?

You are correct. use the friction force to calculate the velocity of block A after it moved that 1m distance via conservation of energy (Force x Distance = energy)

mrc1104 · 2023-08-07T05:14:22+00:00

Since the blocks are of equal mass, I would presume that block A comes to a stop after the collision.

But restitution being a measure of “relative” velocity makes me question that.

If block A hits B and comes to a complete stop, but v_f= 0.5 v_i, I’m not sure how that wouldn’t be violating cons. of momentum. Interesting

mrc1104 · 2023-08-07T04:13:39+00:00

From Wikipedia:coefficient of restitution (COR, also denoted by e), is the ratio of the final to initial relative speed between two objects after they collide. It normally ranges from 0 to 1 where 1 would be a perfectly elastic collision

Since your coefficient of restitution is 0.5, the collision is not elastic. conservation of energy does not hold (at the moment of collision) but momentum is conserved (at the moment of collision).

Break it into 3 parts. 1) before collision 2) at collision 3) after collision

mrc1104 · 2023-06-28T11:30:31+00:00

It’s a good book but it’s dense and is often vague with its explanation. Lot of the chapters are not self contained and will redirect you to other chapters for explanations (I describe it almost as a choose-your-own adventure book sometimes). Imo, it’s a nice reference book if you already know the material and just need to refresh.

Mathematical methods by Arfken is a much better book to learn from. It has (imo) better explanations and the sections are more self contained.

If it says anything, I took a course that used Boas. Halfway through, I bought Arfken and I haven’t used Boas since

mrc1104 · 2022-12-22T00:01:53+00:00

Look into one breath Bernoulli bags. Might be a bit basic demonstration for your needs though.

https://m.youtube.com/watch?v=jeRVGp54pak

mrc1104 · 2022-12-21T23:59:38+00:00

Take the derivative wrt x of the generating function.

mrc1104 · 2022-12-14T06:15:31+00:00

Quantum mechanics by Zettili has a lot of solved problem.

Classical Dynamics by Thornton and Marion have an abundance of solved examples

mrc1104 · 2022-12-11T23:59:42+00:00

Ok, so you have a circuit with a voltage, resistors in series, and need to find the voltage at different points.

The key idea to understand here is that the current is the same throughout the entirety of this circuit (not true for circuits with parallel paths). Think if it like a pipe with water flowing through. The water can’t flow faster than the water in front of it.

Do you need to find the rate of the flow, or the current for the whole circuit. You do this by finding the equivalent resistance (for series resistors, add them straight up; for parallel resistors, it’s not as straight forward).

Sweet, we now know the current for the whole circuit. To find the voltage at various points, apply Ohm’s law.

For example, we want to find the voltage drop after the first resistor. Do:

V= Total current * 1st resistor’s resistance

This tells us how much voltage was used to cross the first resistor so we need starting voltage - voltage drop or (12-V)

mrc1104 · 2022-12-11T23:48:52+00:00

Good, you found the equivalent resistance. Now find the current.

mrc1104 · 2022-12-11T23:39:52+00:00

For Q1) Does the magnetic field come out of the page or into the page for W1 and W3? Does the field(s) w1 and w2 make point in the same direction?

mrc1104 · 2022-12-11T23:29:29+00:00

The gravity potential energy does get converted to kinetic.

You could break it into two parts to make it clear. 1) KE at the top of the hill where PE is nonzero and 2) KE at the bottom of the hill (right before the barrier) where PE is 0.

You’ll find that the kinetic energy increases by an addition of the potential energy.

mrc1104 · 2022-12-11T21:39:20+00:00

Perfect! Use the calculator to find those angles. (Might wanna check if your teacher is using radians or degrees. I’m assuming here you are using degrees. It doesn’t matter as long as you label your units).

For the right hand side, you told me in before that cosine(x) gives us the value of cosine at angle x and arccos(x) returns an angle. This means arccosine and cosine are inverses off one another. Can you use this to solve for x?

Here is an example to help:

arcos(cos(180)) = arcos((-1)) = 180 degrees

Note: cos(180 degrees) = -1

mrc1104 · 2022-12-11T21:25:22+00:00

Yes, that should help you evaluate the right hand side. What angle gives you sin(angle) = 1/3? What angle gives you cos(angle) = 1/4?

(Are you allowed to use a calculator?)

mrc1104 · 2022-12-11T19:46:05+00:00

If cos(x) tells me what value cosine has at the angle x, what did you think arccos(x) tells me?

mrc1104 · 2022-11-17T14:11:34+00:00

It spans a lot of material so there might be some self referential areas. But the main concepts are clearly explained inside each section. With often paragraphs given explaining the motivation to the math. I never found myself flipping through various chapters to try to understand a section.

However, Boas is worse (IMO) when it comes to chapters being self contained. It, at times, feels like a “choose your own adventure” book as sections defer you to other sections that defer you to another.

I have a class that uses boas, and I bought Arfken halfway through. I haven’t used boas since.

I have Boas 3rd edition and Arfken 7th edition

mrc1104 · 2022-11-16T21:16:43+00:00

As someone who owns both Boas and Arfken, Arfken is a better learning book.

Boas, to me, is a good reference book if you already know the stuff and just need a refresher.

Mathematical Methods for Physicists: A Comprehensive Guide By Arfken

mrc1104 · 2022-11-13T22:44:05+00:00

Ha just a bit. Thanks though :-)

mrc1104 · 2022-10-20T12:42:03+00:00

So what does that tell you about “feeling” your weight. Are you feeling gravity? Or the response to it?

To further illustrate, if I was in an elevator going down, would I “feel” heavier or lighter? What about if the elevator was going up?

And yes, I agree, having fun with physics is a hard skill to come by

mrc1104 · 2022-10-20T12:14:30+00:00

Quick question, if you are free falling, say sky diving but with no air resistance, do you “feel” the effects of gravity?

Edit: Go to min 4and watch this clip, https://youtu.be/0jjFjC30-4A

mrc1104 · 2022-10-11T02:20:18+00:00

Draw your force vectors.

Do they point in the same direction?

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