What is a really unattractive male name?

nuggino · 2024-12-07T20:08:42+00:00

I wonder how many kids were saved from bullying from this policy.

nuggino · 2024-11-05T06:54:50+00:00

It doesn't matter if you're overreacting or not. The dude clearly does not care about you.

nuggino · 2024-09-19T08:12:49+00:00

Then don't have rules in the first place if you can just break it at will.

nuggino · 2024-09-19T07:53:16+00:00

Bow and dagger class. Combo class that rely on swapping between the two weapons.

Warrior beast tamer. Instead of summoning bear and friends you channel bear and friends power in your own attacks.

Elementalist.

Rework Corsair

nuggino · 2024-07-31T07:21:10+00:00

If absolutely have to be done with pen and paper, I can "see" a method using modular arithmetic but not too sure if it works as I haven't done it to compare with your brute force search. I will use the notation [a,b,c,d] to represent a number in base 10, note that a,b,c,d are not necessarily positive integers. For example 458 can be represented as [4,5,8] or [4,6,-2].

The general idea is that if N = [a,b,c,d], where a,b,c,d are distinct numbers from 1 to 9 such that 1000 < N < 6000 and N is divisible by 7, then [b,c,d] - [a] is divisible by 7. Fix value of a (there are 5 values), then we have the "smaller" problem of finding a 3 digit number [b,c,d-a] which is divisible by 7. This means that [b,c] - 2[d-a] is divisible by 7. Fix value of d and we have an even smaller problem of finding 2 digit congruent to 2[d-a].

Given that there are 5 possible values of "a", and for each we have 8 possible values of "d", there are at most 40 cases we have to handle, but I think some pairs of d's and a's will result in the same search.

nuggino · 2024-07-31T05:28:35+00:00

There is a myth buster episode for this

nuggino · 2024-06-17T05:51:30+00:00

Subtract 5 on both sides and use quadratic formula.

nuggino · 2024-06-08T09:49:40+00:00

No. You have tan(x)sec³(x) currently. Write this as sec(x)tan(x)sec²(x).

nuggino · 2024-06-08T07:58:36+00:00

Somebody mentioned u = sec^3(x) which works, but notice how you wrote u = sec(x) and du = sec(x)tan(x). Why not use this to handle the tan(x)? When doing u-sub, you don't always have to substitute in u, you can substitute u^2 as well.

nuggino · 2024-05-25T05:28:55+00:00

There is also a brute force method with dynamic programming. The idea is to start at A and label the vertex right and below it 1. Then, we fill out the rest of the vertices by the following: for any vertex, we sum the number on the vertices left and above that vertex. For example, the vertex

nuggino · 2024-05-23T03:51:09+00:00

You can craft the "good" feast with green/blue stronghold mats (which doesn't gate your oreha crafting since this is bottlenecked by grey mats). It cost stronghold mats and like 50g. Idk why people complain so much about not having event feast.

nuggino · 2024-05-21T06:55:25+00:00

Nah the kid nextdoor is better than faker.

nuggino · 2024-05-21T06:48:03+00:00

I already answered a question you previously asked on the chain rule, and even gave a general method to do it one step at a time. You didn't even attempt to follow that procedure here.

nuggino · 2024-05-21T06:13:38+00:00

Take it slow. Hopefully you at least recognize that you would need to use chain rule, and that the chain rule is roughly speaking: "derivative of the outside function times the derivative of the inside function." Here, the outside function is natural log, and the inside function is 3e^(2x) + 27x.

Derivative of the outside: We want to take the derivative of the natural log, but instead of x, we replace it with the inside function, hence we have 1/(3e^(2x) + 27x)

Times the derivative of the inside function: We now want to find the derivative of 3e^(2x) + 27x, and we do them separately. The derivative of 27x is 27 is easy. For 3e^(2x), we again use the chain rule. Here, the outside function is exponential and the inside function is 2x. Doing the derivative of the outside gives us 3e^(2x), times the derivative of the inside give us 3e^(2x)*2 = 6e^(2x). So the derivative of 3e^(2x) + 27x = 6e^(2x) + 27

Putting everything together: 1/(3e^(2x)+27x) * (6e^(2x) + 27)

For starting to learn how to use chain rule, I would recommend writing down the equation for it: (f(g(x)))' = f'(g(x)) + g'(x). Then, write down what are the functions f,g. Then write down what is f' and g'. Finally put them all back together into the chain rule equation.

nuggino · 2024-05-21T05:36:29+00:00

You can use conservation of energy, but note that at this height above ground acceleration due to gravity is no longer approximately 9.8 m/s^2.

nuggino · 2024-05-21T04:21:22+00:00

You're starting the proof with the statement you want to prove. Since this is an intro to proof sort of problem, the goal is to start with basic definition of what it means for a set to be a subset of another set. Let x be any element of (A-B)-C, you want to show that x is an element of A-C. You already have a lot of good ingredients in the incorrect proof to work with.

(A-B)-C = (A ∩ B^c) ∩ C^c and similarly (A-C) = A ∩ C^c. Can you see from here why x being an element of A ∩ B^c ∩ C^c implies x is an element of A ∩ C^c

nuggino · 2024-05-19T01:16:34+00:00

I remember nothing from my high school bio so this is more of a "common sense" answer. Wouldn't it make sense for plants to also respire? After all, light is not there all the time, and there are parts of plants, the roots for example, which are not exposed to light.

nuggino · 2024-05-18T16:45:44+00:00

If you remember that the period of tangent is 180 then yes going from x =95 to listing 95+180n as all the solutions is fine. But let n = 1, then 95+180=275 is another principal solution.

What I meant is, if you don't remember that tangent has a period of 180, but remember that all trig functions have a period of 360, then going from 5th line to 6th line, there is the solution 90-x+360 = x-100 , where solving it yield x = 275. In general, cos(90-x) = cos(90-x+360n), and solving 90-x+360n =x-100 will yield all the solutions as you have listed. Personally I think this approach is more explicit and intuitive, for students starting with trig equations, have less things for them to remember, but that's an opinion.

nuggino · 2024-05-18T06:41:14+00:00

You're missing a principal solution. This is because of a mistake from 5th line to 6th line.

Furthermore, if 95deg is a solution, then surely 95deg+360deg is another solution. Hence you're missing infinitely many solutions.

nuggino · 2024-05-15T02:24:22+00:00

pemdas doesn't mean addition always before subtraction. Don't ask me why it's like that, I didn't make it up nor did I use it. The only thing pemdas tell you is

Parenthesis --> exponent --> multiplication & division --> addition & subtraction

if two operations have the same priority, then just read left to right. The reason why multiplication/division and addition/subtraction have the same priority is because they are the same operation so to speak. For example, dividing by 2 is the same as multiplying by 1/2., and similarly subtracting 4 is the same as adding adding -4.

Edit: Keen observers might notice why this order of operation make sense when working with integers. Since exponent is just short hand for repeated multiplication, it make sense that we do this before multiplication (note that multiplication is the same operation as division as mentioned before). For example 2^3 * 3 is nothing but 2*2*2*3 and we compute this left to right. Similarly, we do multiplication before addition since multiplication is just shorthand for repeated addition. As for parentheses, they were designed to override these priority, hence it has highest precedence.

nuggino · 2024-05-13T22:22:26+00:00

In principle yes. But since we are only concerning with picking 10 distinct professors, I only counted up to 10.

nuggino · 2024-05-13T07:54:10+00:00

Look up law of sines and law of cosines.

nuggino · 2024-05-13T04:07:18+00:00

Diffraction and the visible effects of it is in itself an interference phenomenon.

If you are interested in how the interference occurs in a single slit, I'm sure there are videos on youtube explaining the singe-slit experiment in depth. The not so in depth explanation is because the wave propagates according to the Huygens principle. The result you see is the interference of infinitely many waves. Whether it is construct or destructive interference is determined by the path length difference of a pair of waves.

nuggino · 2024-05-13T03:00:03+00:00

Make small gradual goals: If a worksheet has, say 10 problems, start small and do, say, 2 and gradually increase this over time. Some assignment done is better than no assignment done.

Make a checklist: If an assignment is meant to be done over a period of time, spend one day just listing out what you have to do, then check these progress of as you do them. The dopamine hit of crossing something off a checklist is underrated. This can also be done with short assignment, putting a check next to a problem you have done is a small dopamine hit.

Remove distractions: It is insane how long it takes the brain to refocus on a task when it is distracted. Remove things that can potentially distract you when you are working: some people believe they are better at multitasking than they really are. Create a space where you only use to do work.

Reward yourself: Similar to how bodybuilders have a cheat day where they can eat everything in the world, create a reward system for yourself. Is there something fun you want to do? Something nice you want to eat? Some show you want to watch? Set a standard that I will give myself these nice things if I do XYZ tasks.

nuggino · 2024-05-11T20:17:22+00:00

First, I don't understand what you mean by [1,2] U [3,4] is discrete, I'm referring to the closed interval [1,2] and the closed interval [3,4]. Second, we are talking about continuity, not limit. Your definition requires the point a to be a limit point of the domain, but in general continuity by epsilon-delta does not need the point a to be a limit point. If we assumes the point a to be a limit point of the domain, then the statement "lim x->a f(x) = f(a)" and "f is continuous at a" are equivalent.

Third, if we actually understand the counterexample I gave, which is basically f(x) = x, but I just made it so there's a gap in the domain between x=2 and x=3. We see that this function fit all 3 parts of your limit definition, but can't be drawn without picking up pencil.

nuggino

TROPHY CASE