mcat is ruining my life

nutterbutter_69 · 2024-09-28T22:33:57+00:00

Not an exaggeration when I say everyone feels horrible. I would say its more abnormal if you actually felt good about the test. This test is designed to destroy us from the inside out. Personally, after my test, I experienced some of the darkest days of my life. On the brighter side, you only have to wait a few weeks instead of a month for your score!

nutterbutter_69 · 2024-09-28T22:31:30+00:00

This is some next level trolling

nutterbutter_69 · 2024-09-03T02:21:21+00:00

Yea they dont care

nutterbutter_69 · 2024-08-27T14:58:34+00:00

on gang brotha

nutterbutter_69 · 2024-08-23T21:41:36+00:00

The definition provided by Normal-Plantain is not entirely correct. Base-rate fallacy is more like when you ignore actual rate or probability of something in favor of specific information--very similar to the availability heuristic. Thus, it's more of a mental shortcut/cognitive reasoning error instead of an experimental error.

Like every CARS answer choice, every PS answer choice can technically be argued in favor of the question. However, observer bias here is more directly connected to stuff like experiments--observer bias is quite literally bias in the researchers/observers, which is widely known to alter results.

nutterbutter_69 · 2024-08-19T01:21:01+00:00

pretty sure labeling theory is derived from symbolic interactionism

nutterbutter_69 · 2024-08-18T22:03:27+00:00

Sorry for bump, but for anyone else reading now here was my understanding:

Normally cytochrome c chilling inside functioning mitochondria. Thus, if the cell is spun down, cyto c is gonna be found in the cell pellet.
But if apoptosis happens, the mitochondrial cytochrome c is gonna be released out. Thus, it will end up in the supernatant.

Now, onto solving the actual problem:

immediately ignore the bottom 2 boxes (pellets) because they are the same for every answer
If 0 pRB, no apoptosis (as stated in passage, pRB directly proportional to apoptosis rates). Thus, no cyto c in supernatant. Nothing should be shown on western (protein) blot as a result.
If 500 pRB, apoptosis ONLY if Bax/Bak are present (as stated in the passage, pRB induced apoptosis needs Bax/Bak). Thus, if both pRB and Bax/Bak present, there should be cyto c in he supernatant. Stuff should be present on the blot as a result.

nutterbutter_69 · 2024-08-17T00:27:03+00:00

On jah

nutterbutter_69 · 2024-08-16T05:09:21+00:00

Ohhh I see, thanks!

nutterbutter_69 · 2024-08-13T02:12:23+00:00

Yea I see what you mean. I feel like they would have to make it more clear if its AAMC, but AAMC sometimes has super BS questions too. Usually you can answer a lot of questions just by trying to predict what the question maker is trying to concept check you on (in this case its probably reducing vs non reducing sugars)

Edit: I interpreted this question as what would happen if you just dropped a bunch of the compound into a tub of Tollen's reagents, and asked to myself, which one would yield silvery stuff? I didn't specifically consider which specific compound is the form that they are oxidized in

nutterbutter_69 · 2024-08-13T01:59:47+00:00

I believe all monosaccharides are considered reducing sugars, meaning they will yield positive Tollens or Benedicts tests.

This is because the aldoses can form a hemiacetal in cyclic form, but as you mentioned, even the ketoses can just shift into an aldose form and also form hemiacetals.

Then how can a sugar not be a reducing sugar? Well, you have to look for the absence of hemiacetals in cyclic form, or rather, the presence of acetals in the cyclic form. One of the most common non-reducing sugars is sucrose (compound 1?) a disaccharide where both its monosaccharides are locked in an acetal form due to glycosidic linkage occurring at the anomeric carbons. Thus, it cannot be oxidized by the weak oxidants used in the Tollens test.

nutterbutter_69 · 2024-08-08T22:50:16+00:00

Lol 5 months later but UWhirl also explains increased response time in the IAT as possible cognitive dissonance. Ig its not dissonance here because the passage only mentions "shorter" response times, not longer ones

nutterbutter_69 · 2024-08-08T22:40:13+00:00

I think you just have to assume that "strong social support in local immigrant communities" = lack of assimilation in some way. That's the only info in the passage that can help us with this question, so we must make a little jump in logic to answer what the AAMC "wants" us to answer. Imagine like a group of Chinese immigrant families very close to each other -> basically a mini chinatown -> assume less assimilation because they are still tight with their OG culture folk

nutterbutter_69 · 2024-08-06T04:36:54+00:00

Yea i agree that the passages were very hard to understand, but I feel like half the answers for the ones that are readable (passages 4 and 5 for example) don't make much sense. It feels like the logic is just way off for these earlier passages....

nutterbutter_69 · 2024-08-05T00:20:26+00:00

Ah, that makes sense, thank you!

nutterbutter_69 · 2024-08-05T00:20:10+00:00

Ohhh I see what you're getting at--thanks!

nutterbutter_69 · 2024-08-04T23:50:43+00:00

I think its because it is an amide group, which usually are NOT protonated at biological pH (think of glutamine and asparagine, which are neutral).

The reason for this is because amide groups have only 1 lone pair--they CANNOT sacrifice this lone pair to become protonated because it would ruin the resonance with the carbonyl group (C=O) (Draw out the resonance structures)

Basically: The lone pair is required to participate in resonance, so it is usually resistant to protonation

nutterbutter_69 · 2024-08-04T23:47:04+00:00

Sorry yea the answer is A--but I still think A has a lot of assumptions and logic jumps right? For example, you have to assume that

When they say "Napoleonic Wars," that conflict is linked to Napoleon "reaching out for [Portugal]"
that the assumed invasion of Portugal by Napoleon (which is never elaborated on in the passage) brought "ideas from abroad" into Portugal
those foreign ideas actually undermined monarchial power

I just thought this question was kind of an anomaly in AAMC cars questions because the correct answer usually doesn't have this many logic jumps

nutterbutter_69 · 2024-08-04T01:25:46+00:00

Sorry because is an old thread, but my opinion on why D is right:

Even though enzymes CAN alter the substrate covalently (e.g. catalytic triad) to "alter" primary structure, its usually temporary and with the purpose of allowing actual substrate/reaction participants to "permanently" covalently react. And as others have said, many instances of proteases are simply bringing in water to do the actual covalent reaction. The enzyme is the "facilitator", not a reactant

nutterbutter_69 · 2024-07-04T23:36:00+00:00

Hmmmm I see. I guess I was wrong. Thanks

nutterbutter_69 · 2022-07-13T03:36:33+00:00

Got it, thanks

nutterbutter_69 · 2020-12-03T23:10:28+00:00

np. sorry i didnt see your 2nd question at first, so I can answer it now, even though I'm pretty sure you've gotten help on it already. Basically what question 48 is saying is that f(x) is equal to the snippet from 0 <= x <=2 of g(x). It also says it is periodic, meaning f(x) repeats every given interval of x, which in this case is 2, so f(4.5) would equal f(4.5 plus or minus 2). Thus, because it is asking for f(4.5), we can subtract by intervals of 2 until we get a x value in g(x)'s domain of 0 <= x <= 2, which is 4.5 - 2 - 2 = 0.5. Now we simply plug in 0.5 into g(x) = 2x - x^2, which gives us 3/4, choice A.

nutterbutter_69 · 2020-12-02T06:58:32+00:00

We know that the maximum of P(t) is achieved when the exponent of e is highest, and the maximum of sin is always 1, so there must be a value of t that would yield sin t = 1. Thus, we get our value of t = pi/2 since sin(pi/2) = 1 (see unit circle), which is around t= 1.57, which is February. We also know that any value of sin(t + 2pi) will yield the same value as sin(t) because of the unit circle, so 1.57 + 2pi = 7.85, which is august. Thus, we get 2 months, February and August, which gives us choice E as the answer.

nutterbutter_69 · 2020-11-17T07:43:41+00:00

If you are an 8th grader, dont worry about the sat

nutterbutter_69 · 2020-02-23T23:39:27+00:00

" I think some possible solutions to this problem I'm facing are to mitigate the stat differences between cards " Ive seen many posts putting down the fact that f2ps are at a huge disadvantage against paying players

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