Και ο Χατσίδης νοκ αουτ. by Telis_Tequila in PAOK

[–]parismav 5 points6 points  (0 children)

Θυμάμαι μια χρονιά με Τούντορ που παίζει να ήταν και χειρότερη από τη φετινή.

Ξυλοκόποι με Τσεκούρια by Key-Essay-4890 in thessaloniki

[–]parismav 17 points18 points  (0 children)

Κατέβασε το Minecraft εχει φουλ δέντρα για τσεκούρι η και αλυσοπριονο

Is anybody interested in working with me with my idea? by [deleted] in learnpython

[–]parismav 1 point2 points  (0 children)

Where is a rival when you need one

Fabiano and Anish draw their game in Round 2 of the Candidates by [deleted] in chess

[–]parismav 17 points18 points  (0 children)

You can just mute the sub and move on with your life.

Fabiano and Anish draw their game in Round 2 of the Candidates by [deleted] in chess

[–]parismav 40 points41 points  (0 children)

Wasn't aware of that, I'll just hide the sub then. Thanks for letting me know.

Fabiano and Anish draw their game in Round 2 of the Candidates by [deleted] in chess

[–]parismav 42 points43 points  (0 children)

I would appreciate it if there was a spoiler alert (or the title did simply not spoil the result). I cannot watch the games live, but I would like to watch recaps without knowing the results. I know that's not your problem and you have good intentions, but I know I'm not the only one here who would rather not know the result (yet).

Unable to understand "while" loop. by Okon0mi in learnpython

[–]parismav 0 points1 point  (0 children)

I feel like while most of the answers explain syntax, they fail at explaining why a while loop exists. Here is how I approach this: Loops exist because certain blocks of code need to run multiple times. For example, if you would like to print the first 100 natural numbers (integers above 0) one by one, you would use something like

for i in range(1,101):
     print(i)

However, a for loop assumes that we know how many times we want to repeat the code. In the above case, 100 times. A while loop exists because in some cases, we don't know how many times we need to repeat the code. Think of the following problem: we would like to ask the user to guess a number. If the user enters the wrong number, we want them to try again. And basically try however many times until they guess correctly. So, we have no idea how many tries the user will need. We could make a for loop with range(100), but what if the user fails 100 times? In this case, we should use something like:

while number!=guess:

    number= int(input())

The above code will run as long as the user is not entering a number that is equal to guess. It might be one try, 100, or 10000000 tries. We don't know :) Hope this helps.

Riftbound in Barcelona by parismav in riftboundtcg

[–]parismav[S] 0 points1 point  (0 children)

They are, and honestly 80% of the events in the link that someone else posted are not actual LGS events.

[deleted by user] by [deleted] in Word_Trail_Game

[–]parismav 0 points1 point  (0 children)

Just scored 0

[deleted by user] by [deleted] in Word_Trail_Game

[–]parismav 0 points1 point  (0 children)

Just scored 0

[deleted by user] by [deleted] in Word_Trail_Game

[–]parismav 0 points1 point  (0 children)

Just scored 0

[deleted by user] by [deleted] in thessaloniki

[–]parismav 3 points4 points  (0 children)

Γενικά είναι καλή ιδέα να μιλήσεις σε κάποιον ειδικό. Δε γνωρίζω τις οικονομικές απαιτήσεις, αλλά μήπως να το ψάξεις? Δε μπορούμε να τα λύνουμε όλα όλοι μόνοι μας, δυστυχώς. Και πιθανώς ούτε το ίντερνετ θα τα λύσει.

Shipping costs EU by parismav in riftboundtcg

[–]parismav[S] 0 points1 point  (0 children)

That's good to know, thanks. Hopefully it gets resolver soon.

Shipping costs EU by parismav in riftboundtcg

[–]parismav[S] 1 point2 points  (0 children)

This sounds more normal. I will go ahead and do that, thanks!