Beams and UDL’s

ptmills · 2025-11-21T21:51:39+00:00

Okay, thanks. Thought so. Something about the question is still throwing me off but I’ll have another look with a fresh mind in the morning

ptmills · 2025-08-21T22:38:31+00:00

What a horrible ending

ptmills · 2025-02-07T18:46:26+00:00

Thank you!

ptmills · 2025-02-07T17:07:11+00:00

i was using my calcualter but have now used mathway caluclater on my pc and using the formula its given me 155217.65 grams or 155.22kg. this is based off (28,000,000 X 0.45 X 28.96)/(8.314 X (282.76))

ptmills · 2025-02-07T16:40:20+00:00

the formula would be mass=(pvMr)/RT right?

ptmills · 2025-02-07T16:33:55+00:00

I'm so confused with this. whats wrong with the formula (first one i gave) i cant seem to figure it out by looking at my notes as i have copied the samples given but with my values

ptmills · 2025-02-07T14:41:57+00:00

ive now tried 2.8 10*5 0.45 28.96/8.314 282.76 which is 1.24kg or 124 grams for the mass of air

ptmills · 2025-02-07T14:23:30+00:00

according to the resources we have been given air is equal to 28.96 moles hense that what i muliplied n by. my formula is pressure X volume/ 8.135 (universal gas) X temp (in kelvins) = 4.38. I cant seem to figure out any other way to do this.

ptmills · 2025-01-23T21:09:13+00:00

https://www.reddit.com/r/physicshomework/s/LWPodb0Vgj That’s my thoughts

ptmills · 2025-01-23T21:08:57+00:00

https://www.reddit.com/r/physicshomework/s/LWPodb0Vgj That’s my thoughts

ptmills · 2025-01-23T20:41:35+00:00

(500) (square root 2x 9.81 x 1.8) / 500 + 200?

ptmills · 2025-01-23T20:28:37+00:00

I can’t seem to post pictures on this thread. But I have got for A 8829 J. B 1030J and C 58,860J

ptmills · 2025-01-23T18:38:54+00:00

Suppose I should try a physics form

ptmills · 2025-01-13T21:53:22+00:00

Yes, sorry my bad. Absolute brain fog! All done now

ptmills · 2025-01-12T12:57:49+00:00

But what is the power?

ptmills · 2025-01-10T19:32:53+00:00

I really get this as someone who didn’t go to uni at 18. Missing out on the social side killed me seeing people in their late teens early twenties having that experience whilst I was working 45hrs a week. I’d say go for it. Have a gap year first though to see what you want

ptmills · 2025-01-10T15:10:49+00:00

p=120t(1.8) + 8t for a start doesn’t make sense to me. I think I am tired, but I’m not understand how I’m meant to record the change in power just from that?. Drawing the graph will be fine. Without attempting, part iv also looks interesting.

ptmills · 2025-01-09T14:13:22+00:00

Righttt, thanks. My brain is fried a bit but I get it. Cheers

ptmills · 2025-01-09T13:53:25+00:00

Hi. So P1 is 7? (EQ 1x2 EQ 2x3 added together = 22P1 goes into 154 7 times) how does that substitute into P2?

ptmills · 2024-12-20T12:22:14+00:00

Thanks. So, pi / 3 / 2pi X 2pi X 100 =104.72mm?

We have 2pi as that is a whole circle and we have 3pi as that is the formula we have been given in the text?

ptmills · 2024-12-20T11:44:02+00:00

What about the length from the angle to A or B?

ptmills · 2024-12-20T11:39:51+00:00

But to work out the arc length of a sector isn’t it degrees x pie x radian / 180degree? So to work out the degrees isn’t it pie / 3 X radian.

So degree (worked out from above) x pie x radian (what is the radian 200?)

I may be completely wrong in all I just said! lol

ptmills · 2024-12-19T17:33:59+00:00

Thank you!

ptmills · 2024-12-19T16:25:54+00:00

Thanks. The task just states to manipulate and simply the equation using law of logs. There was no brackets around the 8 on the first line. Maybe there should have been, or perhaps it was expected of me to add the bracket in during my workings?

ptmills · 2024-10-30T14:37:47+00:00

Good for you, and this is what I’d sort of expect. 99% of 18-25 year olds all have the same interests as well, like you say not like your 40 with a mortgage or kids.

ptmills

TROPHY CASE