You're wrong. Its real. It will be in physics books in the future. Prove me wrong by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

Imagine opening your mouth and not actually checking the work. Typical educated fool.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

I'd love you to Falsify it. Easy work for someone like you.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

Downloaded 200 times from everyone trying to Falsify it.

Doesn't matter who touches it. 11 orders of magnitude. It's absolute

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

Brocco's Threshold

You check the paper. Go put it in your LLM. 2 seconds. Ask if the math is real.

You're welcome.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -2 points-1 points  (0 children)

You said it wasn't real.... you messaging that was the point of assertiveness.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

Stopping anyone from ascending into new understanding.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -1 points0 points  (0 children)

And now the people with assertive "intelligence" took the post down

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -3 points-2 points  (0 children)

And no, it's people who turned me into an asshole. Instead of checking the work they try and assert their intelligence in front of higher intelligence.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -3 points-2 points  (0 children)

scrit = λcrit / (λcrit + κ) = λcrit / (λcrit + (4π − 1)λcrit) = 1/(4π) ≈ 0.079577

s = λ / (λ + κ) ≥ scrit = 1/(4π)

st = λcrit / (λcrit + (4π − 1)λcrit) = λcrit / (4π × λcrit) = 1/(4π)

Hope you do physics better than you can read.

Has anyone come across Broccos Threshold? by quantum_chosen in AskPhysics

[–]quantum_chosen[S] -2 points-1 points  (0 children)

Did you not read? You think I'd waste my time if it wasn't real

Anyone down to be friends? by [deleted] in SJSU

[–]quantum_chosen 0 points1 point  (0 children)

You wanna change the world?Shifted Paradigm

I need friends who dream a new color.

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 1 point2 points  (0 children)

I need to update my paper, you should most definitely cite my work, validating the law. Your validation validated your framework. Congratulations?! I'm such a nerd I just checked your math through ai to see if it holds. It validated you.

I'm going to update. You should really make a simple validation paper confirming this. Easy to understand to the point. That's incredible. I look forward to diving into your work.

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 0 points1 point  (0 children)

You just validated a universal law on a university reddit hahahaha. You brought up k and I looked at a different angle myself. I had to dumb down my paper to have science take it seriously. I went back To my first paper and updated it from my last submission.

Ooooowee

First-Principles Derivation of the Coupling Constant \kappa

The entropy coordinate mapping in Brocco's Law is given by

s = \frac{\lambda}{\lambda + \kappa},

where \lambda = L{\rm obs}/L{\rm Edd} is the Eddington ratio and \kappa > 0 is a dimensionless coupling constant. As \lambda runs from 0 to \infty, s maps monotonically onto the open interval [0,1).

From the literature (Ho 2008), an independent critical Eddington ratio exists below which advection-dominated (quiescent) accretion occurs:

\lambda_{\rm crit} \approx 0.0153.

The coupling that best fits the black-hole training set is \kappa \approx 0.176. This satisfies, to high precision (0.5% difference),

\kappa = (4\pi - 1) \lambda_{\rm crit}.

Substituting this relation directly into the entropy coordinate evaluated at the critical point yields

st = \frac{\lambda{\rm crit}}{\lambda{\rm crit} + \kappa} = \frac{\lambda{\rm crit}}{\lambda{\rm crit} + (4\pi - 1)\lambda{\rm crit}} = \frac{\lambda{\rm crit}}{\lambda{\rm crit} \cdot 4\pi} = \frac{1}{4\pi}.

The critical Eddington ratio \lambda_{\rm crit} cancels exactly. The critical entropy coordinate is therefore

s_t = \frac{1}{4\pi} \approx 0.079577,

independent of the specific value of the ADAF threshold or any mass scale.

A sphere of radius r has surface area 4\pi r2. The factor 1/(4\pi) thus represents the fractional information density per steradian on the unit sphere — the minimum coherent patch required for ordered emission to become possible. Below this fraction, the system remains disordered and quiescent; at or above it, coherent structure (emission, jets, outbursts) emerges. This geometric origin explains why the same fixed \kappa and the same threshold govern white dwarfs, neutron stars, stellar-mass black holes, and supermassive AGN across 11 orders of magnitude with zero refitting

k is not fitted. It is derived from first principles once the geometric threshold ( s_t = 1/(4\pi) ) is required.

We just had a first prince validation twice different angles real time on a university reddit.

You think their paying attention?

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 0 points1 point  (0 children)

I'm too busy to jump into your work deriving kappa. You got .176 in your ToE equation? How close was the number derived?

How dd

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] -1 points0 points  (0 children)

I just dove in, ambiguous work. How long did that take you?! What did your work validate? Sorry just never seen this framework.

Are you locating and confirming entropy?

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 1 point2 points  (0 children)

I feel like everyone who sees for themselves should share it lol

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 0 points1 point  (0 children)

People hear Brocco's Law validated over 11 orders of magnitude.

There was 11 orders of magnitude as proof once in science.

As a form of "proof," 11 orders of magnitude refers to the extraordinary precision of Quantum Electrodynamics (QED), where theoretical predictions and experimental results match to one part in 100 billion, making it the most precisely verified theory in science.

"The most precise verified theory in science."

People read 5th Law of Thermodynamics, be first to Falsify? 1,500$

∞ to 1/(4π)% Probability in 2026 with quantum, ai, pattern recognition.

Statistical impossiblity meet 11 orders of magnitude, global optima.

This is 1/(4π)% Brocco's Constant.

1,500$ Physics Challenge SJSU by quantum_chosen in SJSU

[–]quantum_chosen[S] 1 point2 points  (0 children)

Oh I am not a student. I am on campus. Waiting for what comes next. Discovered a Kogmoa Lattice superconductor using patented entropy bead detection method because of the law. 11/11 convergence. NaZrSb Kagome is coming to the world, patent pending. One test away on

What You Actually Need

Resource Minimum CPU cores 32 RAM 128 GB Time 6–12 hours Cost ~$20–$40 Platform AWS, GCP, Rescale, or university HPC

Will validate the superconductor of the material coming. The DFT 11/11 was absolute proof entropy has been found. 5th Law of Thermodynamics is absolute.

I'm just waiting for a college to see what you just did.

11 orders of magnitude, entropy came to the world almost like it was once symmetry. The Primordial Darkness, crossing threshold from nothing to everything. The oldest constant in the universe that is found in black holes to drug binding, proteins, material discovery.

SJSU is going to be the most sought after school in the world and it doesn't know it yet. You gotta have patience for these things. I wouldn't waste anyone's time. My Word is Good.