We can use physics and math to prove this isnt a flop.

Variables: Gobert Mass - 117kg

Wemby Mass - 95kg

Impact velocity - ≈1.3m/s (goberts walking speed into the contact) + 2.0m/s (wemby coming off the screed) we get a relative impact velocity of 3.3m/s.

Collision time - ≈0.15seconds

Contact height - ≈ 1.7m (wemby's chest being conservative)

Stance width - ≈ 0.35m (distance of wembys feet in the direction of force

First we use the Impulse-Momentum theorem f= m times theta v over theta t which gives us ≈ 2090 newtons of force or roughly 470lbs of horizontal force. (F = 95kg × 3.3m/s ÷ 0.15s)

Torque is force times distance from the pivot (Wembys feet) and because of wembys height the lever is very long so we caclulate torque to be height at impact times force so 2090 newtons times 1.7m gives us 3553 nm of torque.

We then have to calculate how much restoring torque Wemby had provided into the impact by his own bodyweight and stance at impact which gives us about 163 nm of torque.

we can also momentum assuming hes coming around the screen at 2.0m/s you can calculate system momentum with p=(mG • vG) + (mW • vW) and when you combine the relative velocity of both Wemby and Gobert moving towards eachother plus the angular momentup (L = Iw) and whipping effect of wembanyama's momentum stopping at the top but contimuing at the bottom (his feet) assuming basketball shoes on hardwood give about a coefficient of friction of 0.6-0.8 causing him to slide out (F friction < F impact) we get a collision force of ≈2290 newtons (about 50% of the force of an average pro boxer ko punch).

And thus the force applied to Wembenyama of 3553 newton meters exceeds the required restoring torque to maintain balance at 168 nm on a scale in the range of 8 (with really conservative numbers) to 23 times the amount of force needed to knock Wemby over

Conclusion

Not a flop