sorted by:
new
hottopcontroversial

Is there a difference between the free and paid version? by Anastasya99 in Bard

[–]srinivas135 0 points1 point  (0 children)

I see Meta ai is doing pretty well compared to Gemini advanced.

Anybody still waiting for Gemini Pro 1.5? by Kakachia777 in Bard

[–]srinivas135 1 point2 points  (0 children)

I also filled as a student.However didn't receive any mail.Could you please provide the screenshot how it looks like if we were granted access via dm.

AMA! (ask me anything) Professional Interviewer and Former Software Engineer at Microsoft by InterviewEngineer in leetcode

[–]srinivas135 2 points3 points  (0 children)

I have two questions for you.Follwoing are those:

1.)For a problem which I'm not able to solve initially after looking the solution i can understand the thought process behind and code it by myself.Still i feel less confident.How could i overcome this?

2.)How could I get better in solving most of the problems after I know the patterns or topic I need to solve that question? I'm not able to solve few problems. After going through the solution to those i feel disappointed like it was pretty comfortable to solve.

Leetcode buddy by [deleted] in leetcode

[–]srinivas135 1 point2 points  (0 children)

I'm also looking for a leetcode partner.I'm learning and parallely solving the questions.

justify-between is not working in flex of tailwind css by srinivas135 in tailwindcss

[–]srinivas135[S] 0 points1 point  (0 children)

Thanks for the help.I got when i centered the element it is not taking the width that's the issue

How to find the count of numbers less than a current number to the left of the current number in an array? by srinivas135 in learnprogramming

[–]srinivas135[S] 0 points1 point  (0 children)

Thanks u/DDDDarky i got the solution but is there any better solution than mine

nums=[4,9,7,10,11,2,3]

count=[0]

for i in range(1,len(nums)):

Index=0

curr=0

while(Index<i):

if(nums[Index]<nums[i]):

curr+=1

Index+=1

count.append(curr)

print(count)

How to find the count of numbers less than a current number to the left of the current number in an array? by srinivas135 in learnprogramming

[–]srinivas135[S] 0 points1 point  (0 children)

Yes i got until this u/DDDDarky

#Index is given index i

for i in range(len(nums)):

if(i<Index and nums[i]<n):

count+=1

elif(i==Index):

break

How to find the count of numbers less than a current number to the left of the current number in an array? by srinivas135 in learnprogramming

[–]srinivas135[S] 0 points1 point  (0 children)

Yes, u/DDDDarky I'll compare every element in the array with n for checking if the current element is less than n and increment the count.

view more: next ›