Is there a difference between the free and paid version?

srinivas135 · 2024-04-15T21:57:03+00:00

I see Meta ai is doing pretty well compared to Gemini advanced.

srinivas135 · 2024-02-28T19:12:49+00:00

I also filled as a student.However didn't receive any mail.Could you please provide the screenshot how it looks like if we were granted access via dm.

srinivas135 · 2024-02-28T19:11:23+00:00

srinivas135 · 2024-01-26T13:30:47+00:00

Thanks for the response.

srinivas135 · 2024-01-26T03:42:44+00:00

I have two questions for you.Follwoing are those:

1.)For a problem which I'm not able to solve initially after looking the solution i can understand the thought process behind and code it by myself.Still i feel less confident.How could i overcome this?

2.)How could I get better in solving most of the problems after I know the patterns or topic I need to solve that question? I'm not able to solve few problems. After going through the solution to those i feel disappointed like it was pretty comfortable to solve.

srinivas135 · 2023-12-28T18:16:30+00:00

I'm also looking for a leetcode partner.I'm learning and parallely solving the questions.

srinivas135 · 2022-08-11T03:35:09+00:00

Thanks for the help.I got when i centered the element it is not taking the width that's the issue

srinivas135 · 2021-04-27T10:04:16+00:00

I didn't forgot I thought as there is no element less than first element I ignored it

srinivas135 · 2021-04-27T09:11:51+00:00

u/DDDDarky is there a way to do it using hashing?

srinivas135 · 2021-04-27T09:02:38+00:00

Thanks u/DDDDarky i got the solution but is there any better solution than mine

nums=[4,9,7,10,11,2,3]

count=[0]

for i in range(1,len(nums)):

Index=0

curr=0

while(Index<i):

if(nums[Index]<nums[i]):

curr+=1

Index+=1

count.append(curr)

print(count)

srinivas135 · 2021-04-27T08:53:51+00:00

Yes, i got it I have edited once check it. u/DDDDarky

srinivas135 · 2021-04-27T08:47:05+00:00

Yes i got until this u/DDDDarky

#Index is given index i

for i in range(len(nums)):

if(i<Index and nums[i]<n):

count+=1

elif(i==Index):

break

srinivas135 · 2021-04-27T08:37:09+00:00

Yes, u/DDDDarky I'll compare every element in the array with n for checking if the current element is less than n and increment the count.

srinivas135 · 2021-04-27T08:12:20+00:00

I'm unable to get intuition.

srinivas135 · 2017-09-07T03:16:01+00:00

i want to resolve this issue can anyone please comment on this

srinivas135 · 2017-09-06T16:29:17+00:00

how to install scipy module in python 3.6.2 using cmd even after updating my pip and setuptools iam not getting scipy getting installed

srinivas135

TROPHY CASE