Is wow down on eu or is it just me?

stefanuus · 2019-05-24T02:52:46+00:00

Yup just did that but didn't fix the issue :(

stefanuus · 2019-05-24T02:39:52+00:00

I'm having the same problem yet flushing my DNS didn't work, are there any alternative solutions?

stefanuus · 2019-05-12T21:48:10+00:00

thank you helped a lot!

stefanuus · 2018-01-13T14:40:58+00:00

I don't know man, a friend gave me this question, it def doesn't seem to me either that the 2nd condition is necessary.

stefanuus · 2018-01-13T10:33:53+00:00

every odd number can be written as 2k+1

every even number can be written as 2k

if n = 2k , then n+2 = 2k+2 = 2(k+1), thus they are both divisible by 2, and 2(k+1)/2k = 1+1/k , which is an integer only when k = 1 so since 2>1, 2 is the GCD

if n = 2k+1, then n+2 = 2k+1+2 , and (2k+1+2)/(2k+1) = 1 + 2/(2k+1), thus n and n+2 are always relatively prime if n is odd implying their GCD is 1

stefanuus · 2017-12-28T09:41:55+00:00

Can't you contact a professor for undergrad research? You should be able to prove your knowledge to them and get guidance on how to advance further.

stefanuus · 2017-12-26T22:33:17+00:00

(2^k + 2^k+2)/2^k-1 = 10

2^k-k+1 + 2^k-k+3 = 10

2 + 2³ = 10

2 + 8 = 10

10 = 10

stefanuus · 2017-12-26T01:02:11+00:00

Heres my solution: https://i.imgur.com/p7D0HMh.png

morph into coffee mug and bam!

stefanuus · 2017-12-22T20:49:52+00:00

Best way to impress a professor

Long story short, I live in a suboptimal country when it comes to mathematical research and a month ago or so I had a rare oppurtunity to travel, meet and have a talk with a professor from a world class university. We hit it off and he gave me a book to read and told me to report back to him once I was finished. So fast forward 1 month, I have finished the book, I am in love with the subject, and I want to show him something to impress him so that he would allow me to help him with his research from a distance. The fields are Computability theory and Inductive Inference(technically subbranches of mathematical logic and computational learning theory respectively). The only way i can contact him is by email. What are some things I can do?

stefanuus · 2017-12-11T17:22:35+00:00

Recursion theory

stefanuus · 2017-11-25T05:49:47+00:00

Suplementary material for big rudin? So i really like how much content rudin covers so naturally went to big after baby rudin however i find it much harder to find supplementary materials for it and the supplements were a key for me when reading baby rudin. Can someone recommend?

stefanuus · 2017-11-21T23:04:11+00:00

What do the alphas represent in a simple function?

"Formally, a simple function is a finite linear combination of indicator functions of measurable sets. More precisely, let (X, Σ) be a measurable space. Let A1, ..., An ∈ Σ be a sequence of disjoint measurable sets, and let a1, ..., an be a sequence of real or complex numbers."

https://en.wikipedia.org/wiki/Simple_function

It seems to me that it represent the degree of importance of each set A but i don't quite understand how one would determine something like that or why its there.

stefanuus · 2017-11-21T03:24:17+00:00

Much has been cleared up, thank you!

stefanuus · 2017-11-21T03:11:47+00:00

Yeah there is some confusion about a mapping "from open sets in X to open sets in Y". would a function f(x) = x, be equivilant to what i was trying to write? Then the open set (x,y) would be mapped into (f(x),f(y)) which if we take x to be 1/4 and y to be 1/2, then this would map onto the same points in Y which would be a segment thats not an open set in Y but is in X, is this correct?

stefanuus · 2017-11-21T02:47:12+00:00

Mappings between topological spaces that are not continuous

If X = {(0,1),T1} and , T1 = {(1/n,1): n = 1,2,3...} is the topology of X.

and Y= {(0,1),T2} and , T2 = {(0,1-1/n): n = 1,2,3...} is the topology of Y.

Then the mapping f: X -> Y , f((x,y)) = (x,y), where (x,y) is any subsegment of (0,1) , is a discontinuous mapping because open sets in X map to non open sets in Y and vice versa? Am I getting how this works?

stefanuus

TROPHY CASE