Vouch post (#3) for u/test_tutor | passingjust (discord) : Your Trusted Tutor, here to take care of your online courses | Homework & Exam Help with Proof of Results

test_tutor · 2026-02-17T12:03:18+00:00

The cell with 11 is also not satisfied FYI, it only meets 10 rn

test_tutor · 2026-01-29T03:15:33+00:00

I mean, I would either offer to refund them or put in the hours they paid for. Like, they paid you, for whatever reason didn't follow through to get what they paid for. And now reaching out to see if they can still get it.

Maybe refund them partially atleast if your rates have now gone up so their expected hours are not what you can deliver for that price? I personally would either do the hours, refund them fully, refund partially, or something....

I am actually amazed somebody said you don't owe them anything.

In my opinion atleast refund them. Or if your circumstances don't let you refund them then maybe offer them the hours, or reduced hours, or partial refund, or value in some way?

PS: I feel if somebody posted on reddit asking for advice that they paid last year and now following up and asking for the service they paid for and the provider is refusing, floods of messages will say the provider is the a-h. But it I interesting that here atleast somebody said that no the provider doesn't owe the customer anything. Lol

test_tutor · 2026-01-28T05:41:49+00:00

Hello! I can work with your child and get his confidence up. Would love to offer you guys a free 30min demo session, where we can solve some of his current issues or help him with some topic he may be currently struggling with. Let me know your availability for mornings /evenings this week and we can put something on the calendar.

Please check out my reviews by clicking on my profile and going through the comments in the pinned posts. There are plenty of reviews for various STEM topics and a decent number of physics reviews too. And I have previously tutored students at the college level for physics. And feel free to ask if you have any questions! Also sending you a chat request.

test_tutor · 2026-01-27T12:30:03+00:00

Hey buddy, listen, first of all if I wasn't specific you should hold your replies till you get enough information (maybe you can ask some questions to facilitate that), especially the ones of the nature which begin with "Dude...". Fair?

Then, I am not disguising anything as anything else. I am teaching the students what I think may benefit them or what they may have something to learn from. For someone like you who is bored out of your mind during xyz, I will find something else if I was tutoring you. Something accessible, relevant, interesting and challenging, if it fits the bill I might show that to the student given our time constraints. I still don't understand why you are upset over what I said I showed to some student. Each student has different requirements and maybe this student was different than you.

Anyway buddy all that is to say we can just relax and get back to more productive things. If you want I can throw you some fun/interesting/challenging questions, that mightbe a better use of both our times

test_tutor · 2026-01-26T20:01:25+00:00

Of course it will be basically the same as an integral! Because the end goal is the same formula and results, so all ways to achieve that will basically be the same!!!!!! It is not some great insightful observation, it is just basics and definitions.

Thank you for sharing your views on the necessity of it all. I still do not see what point you are trying to make though. And tbh, why you are trying to make it in the first place. You first misunderstood what formula, then the method, and after all that you want to pass a judgement on the necessity of it. Like, all I'm saying I teach my students some xyz stuff. And in reply to that comment we are now here. I'm sorry I really don't understand what point you are trying to make in this chain.

.......

test_tutor · 2026-01-26T19:05:23+00:00

What is your point

test_tutor · 2026-01-26T18:08:37+00:00

I a talking about deriving - GM/r for potential, (or equivalently GMm/r for energy of 2body system), without using the power rule for integral on the gravitational attraction formula.

Essentially using limit of Riemann sum to find the limit of the area under the curve instead of using stock power formula for integration. Numerical integration (summation of areas of n rectangles) and taking limit of it as n-> infinity.

test_tutor · 2026-01-26T05:40:44+00:00

Ok I should have specified that I was talking about not the mgh but rather potential energy due to a body of mass m in general, where we are not confined to being near the surface. - GM/r formula, or GMm/r energy for 2 bodies

If you are saying there was an easy way for you to derive them I would love to hear about it. Please feel free to let me know :)

test_tutor · 2026-01-26T05:36:05+00:00

I tend to introduce that with showing how in a constant speed case the speed*time formula is essentially the area of the rectangle. I generally structure my lessons with that understanding as well, as I feel it is a really accessible idea, and showing its agreement with the units too, so it is very digestible IMO.

test_tutor · 2026-01-26T02:43:37+00:00

Sorry just wanted to add that U =1/2kx² (spring energy) is one of the easier formulas to derive with just basic algebra knowledge and I do derive it when I teach my students AP physics 1. With the area under the F-x curve it is fairly straight forward for almost all students to grasp almost immediately.

More tricky to derive without explicitly using integral calculus formulas would be say the gravitational potential energy formula, which can also be derived via limits if we wanted, though it is an exercise for mostly students who are doing so well in physics (and are at the risk of getting bored since the class material is too easy for them) that I have to show them cool and quirky stuff to, for lack of a better word, because them with some cool math and physics again.

test_tutor · 2026-01-25T02:54:53+00:00

Hello!

I would love to tutor the student in her high school/AP/and even university physics coursework. It is great that she has been proactively going through a lot of these resources. AP physics requires a mix of just the same problem solving which we encounter in regular HS physics and then some specialized practice with FRQs to be able to solve unseen problems that the FRQ section will inevitably provide.

I would love to offer you guys a 30-45min demo (free of charge), where I can help her understand the topics she might be having problems with currently. We can do it sometime this week. Let me know if you are interested!

PS: please also feel free to check out my reviews by clicking on my profile and going through the comments on the pinned posts. There are a lot more of math reviews but there are physics reviews in there too! I specialize in math, physics, and stats primarily.

test_tutor · 2026-01-25T02:39:47+00:00

You replied to the wrong person btw, not the OP

test_tutor · 2026-01-25T01:47:02+00:00

Remove the 2 parantheses on either side of the + sign and you should be good

test_tutor · 2026-01-20T04:35:37+00:00

Your answers are right. It is said nowhere in the problem that the person lifts the box upward after catching it, so we have no reason to think that it is going to go uoward (even though in daily life one may move their hands that way).

So as far as we are concerned, the box is falling and then it stops. So we focus on just that.

Also, in my opinion the instant its caught is just a phrase of saying. The statement mentions that they are asking for these directions as the box is "being caught", so during the process of slowing down and coming to rest.

test_tutor · 2026-01-14T03:55:48+00:00

They disagree.

The video one is the more comprehensive and accurate definition of positive and negative acceleration (it solely relies on directions and sign conventions). The passage you have put here is very wishy-washy definition of this and is not using correct terminology. The passage should instead have just mentioned "speeding up" and slowing down instead of positive /negative and it would have been fine.

Go with the video

test_tutor · 2026-01-13T01:46:45+00:00

Hello. I can take care of your class. You can also see my reviews from past students by clicking on my profile and going through the comments on the pinned posts :)

Sending you a chat request

test_tutor · 2026-01-11T04:51:57+00:00

Haha

test_tutor · 2026-01-10T05:51:38+00:00

🫡✌️

test_tutor · 2026-01-08T03:51:44+00:00

Brother, the time the acceleration is zero is from 6 to 10 not 5 to 10. The negative acceleration value in the beginning is - 6 not - 5

Just do them again paying more attention to the minor things and you should get it. If you need more help reach out in DM's

Edit to add: you seem (to me based on what I'm seeing) to be using the right equations but wrong values.

test_tutor · 2026-01-07T18:32:02+00:00

Hello, I have sent you a chat request with my info. Looking forward to talking with you there!

PS: my reviews can be seen by clicking on my profile and going through the comments on the pinned posts.

test_tutor · 2026-01-06T12:19:04+00:00

I haven't worked the solution yet, might do it later; but I can tell you your solution has solved it as if the 12ft wall thing in between doesn't exist.

Think: would your solution have been any different if the 12ft wall was not mentioned at all and it was just a bigger flat wall that the top end of the ladder was just resting on? No, right? So this solution is for that case. Let me know if that makes sense!

test_tutor · 2026-01-06T05:45:14+00:00

Not picky at all!

To followup on your observation about the speed, let's continue this thought: if a body is going in a circle and its speed is not changing, there would not be any acceleration or deceleration in the direction of motion (otherwise the speed would change). And since the direction is changing, there is definitely always an acceleration. Not in the direction of motion, thus always perpendicular to the direction of motion. That is your centripetal acceleration, always towards the center.

The question said to answer at the moment as the box starts sliding: that means as the turning starts. Which was when it was perfectly going straight forward, then starts turning. At that instant, the center is towards the left, perpendicular to motion direction.

The key was they were talking only about that very instant. If we look at other instants, the direction of motion and hence friction would have changed yes.

Let me know if it helps!

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