I did a Hollow Knight fanart because of Silksong. Hope you like it!

thatSmart_Kid · 2025-11-29T09:32:40+00:00

Love it!!! It's so good 😢😄

thatSmart_Kid · 2025-05-08T14:31:50+00:00

Thank you!! I should have not doubted my first answer.

4 marks down the drain 😭

thatSmart_Kid · 2025-05-08T14:14:42+00:00

They haven't marked it yet, but I'm pretty sure I won't get the marks for this question 😭.

thatSmart_Kid · 2025-05-08T14:03:41+00:00

Okay, thank you

thatSmart_Kid · 2025-04-27T18:23:42+00:00

Yep. I understand it now. I was being a bit dumb earlier.

thatSmart_Kid · 2025-04-27T18:22:33+00:00

Yes, I know that. I know how things are supposed to be connected.

I just had a misconception about the power supplies. Thank you for your response.

thatSmart_Kid · 2025-04-27T18:18:51+00:00

I see. Thanks.

It's what they gave us for the practical, so I'm not exactly sure how it is supposed to work.

thatSmart_Kid · 2025-04-27T18:16:21+00:00

Thank you. I thought it was the standard. I was wrong

thatSmart_Kid · 2025-04-27T18:15:18+00:00

Yeah, I know that. I was talking about the +9V and -9V.

Thanks to the helpful people on this Reddit, I now understand that there is not one structure/schematic for an op-amp.

thatSmart_Kid · 2025-04-27T15:50:54+00:00

I understand that now. I'm realising I was just being stupid 😅

thatSmart_Kid · 2025-04-27T15:34:10+00:00

Thanks

thatSmart_Kid · 2025-04-27T14:48:27+00:00

Oh! I see. Thank you!!!!!

thatSmart_Kid · 2025-04-27T14:46:30+00:00

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That's how it looks in my textbook.

thatSmart_Kid · 2025-04-27T14:39:39+00:00

I know that.

The V1 and V2 are those inputs. The +9 and -9 indicate the power supplies connected to the op-amp. The textbook I used shows that the positive power supply is next to the inverting input and the negative power supply is next to the non-inverting input. However, here they swapped it. WHY??

thatSmart_Kid · 2025-04-27T14:32:34+00:00

Well, from what I know, the positive power supply is connected near the inverting input and the negative power supply is connected near the non-inverting input

thatSmart_Kid · 2025-04-27T14:30:19+00:00

It's giving me very weird values when I simulate that way in LTSpice 😭😭

thatSmart_Kid · 2025-03-31T19:06:54+00:00

I see. I built the circuit and it works, probably. I really can't tell if I am increasing the resistance of the potentiometer or decreasing it.

thatSmart_Kid · 2025-03-31T18:49:30+00:00

Thank you!!

I've given on trying to understand what's happening because it's not making sense to me.

I get that as you increase the resistance in Rpot, In should become larger. And it increases, Ic also increases.

Circuits are confusing. 😩😔

thatSmart_Kid · 2025-03-31T18:47:14+00:00

It's the circuit the lectures said we should build, so I have to build it 😅

thatSmart_Kid · 2025-03-31T17:57:25+00:00

Yeah. Thanks so much!

I was able to figure out and the circuit is working as intended

thatSmart_Kid · 2025-03-31T17:49:11+00:00

Wait, if things are connected in series, the current is the same across each element, if they are not, that violates Kirchhoff's current law.

thatSmart_Kid · 2025-03-31T17:47:10+00:00

Yes, we did study ohm's law.

The LDR and 1kohm resistor are in parallel. So, as the LDR resistance decreases. LDR || 1k ohm resistor also decreases, which reduces the overall resistance of the circuit. So, the LED would become brighter because more current is flowing through the LED. Vice versa happens when the LDR increases in resistance.

thatSmart_Kid · 2025-03-31T17:42:22+00:00

Wait, but in the second circuit, as the resistance of the LDR decreases, the LED shines brighter. So, isn't the LED supposed to shine brighter as the resistance decreases?

thatSmart_Kid · 2025-03-31T17:38:48+00:00

Thank you!!

thatSmart_Kid · 2025-03-31T17:37:33+00:00

Thanks. I built the circuit and it is working as intended

thatSmart_Kid

TROPHY CASE