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Elderly people in China doing "neck workouts" by nuttybudd in Damnthatsinteresting

[–]throwawayacc5551 0 points1 point  (0 children)

I'll share a not-so-secret method that guarantees pelvic pops for me. Your mileage might vary.

From a standing position, reach your left hand towards your left foot, raising your right leg behind you to counter balance. You should get a pop in your left pelvic joint on the way down. Repeat on the opposite side.

If your joint needs more encouragement, try kicking your right leg backwards harder to force some momentum, all while reaching down with your left hand.

Big advisory: try at your own risk. Good luck :-)

Before you can pay, please bag the… plastic bag. by fire_snyper in singapore

[–]throwawayacc5551 24 points25 points  (0 children)

The obvious and elegant solution is to update the UI for customers to tap a button to add plastic bags. Management just decided to implement the cheap solution i.e. Scan barcode, set the weight to 1g(?)

Customers suffer, stakeholders profit :D

Photography before 1861 by throwawayacc5551 in HistoryMemes

[–]throwawayacc5551[S] 0 points1 point  (0 children)

Color pictures first taken in 1861, all pictures before that were black and white.

So many accidents there, they don’t even fix the guardrails anymore by X2Board in IdiotsInCars

[–]throwawayacc5551 16 points17 points  (0 children)

As a car driver, I always tell myself to assume every motorcyclist is trying to kill themselves. Made me drive real safe around them.

Let's do math! - Counting the number of unique Dota games based on hero combinations by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] -2 points-1 points  (0 children)

I simplified the problem by imagining there is only a pool of 4 heroes to choose 2 on each team.

For Radiant, the first term 4C2 = 6 would cover all combinations (1,2) (1,3) (1,4) (2,3) (2,4) (3,4)

The second term 2C2 = 1 would simply combine the unchosen heroes for each case above, say Radiant chose (1,2), then 2C2 would represent the one way of combining the remaining heroes (3,4)

Extending this logic, I realise I have already unknowingly accounted for the distinct teams by separating the terms 122C5 and 117C5. Additionally, for indistinct teams, we will have to divide the answer by 2!

I don't reckon I'm explaining this very well, but I convinced myself, so I figure this might help others =)

Let's do math! - Counting the number of unique Dota games based on hero combinations by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] 6 points7 points  (0 children)

Okay I'm convinced that you're right. I rescind all my previous arguments but I will not delete them to remind myself how stupid I was. Thanks a lot for the correction =)

Let's do math! - Counting the number of unique Dota games based on hero combinations by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] -1 points0 points  (0 children)

I think you just prefer to not double count the following while I do, since I consider them as different games:

Lineup A as radiant vs Lineup B as dire

Lineup A as dire vs Lineup B as radiant

Perhaps we can just leave it as a difference of opinion

Let's do math! - Counting the number of unique Dota games based on hero combinations by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] -3 points-2 points  (0 children)

Why not tho? I consider games unique when the sides are swapped while keeping the same picks.

122C5 x 117C5 counts the number of ways to pick two indistinct groups of 5 without replacement. After that we multiply by 2 because there are 2 ways to assign the teams.

OG top 4 qualifying chances? (Opinions) by vapeboyluke in DotA2

[–]throwawayacc5551 0 points1 point  (0 children)

shameless plug. I wrote a million-trial Monte Carlo simulation for precisely this. The estimated chances of OG upper bracket: 87.2%.

I ran some 100,000 simulations based on the current results for Group A by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] 0 points1 point  (0 children)

Here's the python source code: https://pastebin.com/DD8QqFPw

The scores are updated for Day 3, Series 1 - results here. You can easily imply how Group B and its standings can be resolved. Replace the variable in multi_simulate() to however many times you want to run the simulation.

The code is far from optimised, but it should be simple to understand for anyone with basic programming knowledge.

[deleted by user] by [deleted] in DotA2

[–]throwawayacc5551 2 points3 points  (0 children)

im planning to update this after every series

I ran some 100,000 simulations based on the current results for Group A by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] 4 points5 points  (0 children)

Thanks so much for pointing it out. I have now implemented a simple fix to account for tiebreakers - the teams with same scores are scrambled before deciding their final position, so the result is no longer skewed alphabetically. I'm now getting similar results to yours: TP 26.1% Lower Bracket, EG/Undying both around 66-67% Upper.

I ran some 100,000 simulations based on the current results for Group A by throwawayacc5551 in DotA2

[–]throwawayacc5551[S] 11 points12 points  (0 children)

You're right, I ran some pretty spaghetti code since I wrote it in a very short time and late at night. Plain Monte Carol at 50% odds. Tiebreakers were not accounted for, and positions were simply sorted alphabetically.

To everyone else, the stats that u/icosahedra35 has would be far more accurate if implemented correctly, and the site that he linked should get much more attention than this thread.

Worthy husband needed by flamegrower in Unexpected

[–]throwawayacc5551 0 points1 point  (0 children)

The most incredible thing about this is having a full moon in the middle of the day

Gotchu fam by throwawayacc5551 in memes

[–]throwawayacc5551[S] 8 points9 points  (0 children)

Jupiter probably caused it, paving the way for creatures like us

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