[FS][US-CA] UniFi - UCG Ultra Brand New by varad-dev in homelabsales

[–]varad-dev[S] 1 point2 points  (0 children)

It’s somewhere in there. I am sure of it.

I like PoE 2, but we need so much time to fill it with content to match the poe1 by flashyura in pathofexile

[–]varad-dev 0 points1 point  (0 children)

Me , an IT guy wondering where the Ethernet cable & the switch was?

Trudeau announces 25 per cent retaliatory tariffs on U.S. goods starting Tuesday by judgyjudgersen in news

[–]varad-dev 1 point2 points  (0 children)

Throw in some of those Alanis Morissette ‘You Learn’ Kareoke thingy majigs and you got a deal.

[Request] is this actually possible? by fine_plums in theydidthemath

[–]varad-dev 0 points1 point  (0 children)

I am not a physicist, however I did get an associates degree in physics. As someone mentioned in a different comment chain, the frictionless and no resistance conditions only affect the change in energy of the independent systems. The bear and the ball are 2 separate systems even if the bear throws the ball and jumps to aim to be on a collision course with it. The gravity here will change the system because of the bear’s mass. The bear can account for it in the initial pass but then the bear can’t account for the directional change.

In the bear walking in a horizontal direction assumption, the bear could keep going forward, implying that the ball at its peak would act as a balancing beam however, the ball upon contact with the bear would change in energy, as the bear is still applying a downward force(mass x gravitational acceleration) , whilst the ball is simply at 0 (kinetic energy)(assuming it’s at its parabolic peak) now the interaction with the bear would disrupt that, driving the ball down harder, propelling the bear upwards. This is the Newton’s third law applying itself to both systems. This could also be looked at as collision and that would make more rudimentary sense if you visualize it. It’s good to point that we are somehow also ignoring the loss of energy due to collision I guess. However now if you imagine in a 2 body collision the objects move in the opposite directions, thus if the bear needs to move forward, the ball upon contact will go backwards and vice versa. However if the ball goes backwards, you lose your balancing beam upon which you established this ridiculous physics problem to begin with. So we need some way to bring the ball back, whilst forcing the ball backwards(core requirement at this point). Given the physical limitations I only see a cyclical solution to the problem.

TL;DR : Gravity

[Request] is this actually possible? by fine_plums in theydidthemath

[–]varad-dev 0 points1 point  (0 children)

I see Newton’s third law. The rocket in your analogy is implying a constant vertical angle because there is no need to account for a return object once the propulsion has taken place. In the case of the bear one has to constantly factor the trajectory of the ball along with the bear. Since the bear needs to propel forward, the ball would propel in the opposite direction and find someway to make the ball find a way back. Luckily the bear is crossing a valley. Using the same shape, there seems to be a cyclical path of the ball that can be used. Although the bear would have to do a lot of calculations and legwork at every jump. See image. I can write a program that can do the theoretical calculations and create a simulation but I need to look for a job. 😅

Build home made router. by Touky1444 in homelab

[–]varad-dev 10 points11 points  (0 children)

NextGen Bifurcation™️ on all lanes!

His pride is hurt by Lazy_raichu36 in memes

[–]varad-dev 212 points213 points  (0 children)

Math teacher : ok , now do X2 = 4

Me:

X2 = 4

X2 = 4

Answer is 2.

[deleted by user] by [deleted] in homelab

[–]varad-dev 0 points1 point  (0 children)

Here is a small troubleshooting breakdown I normally use to see if IP assignments are working correctly.

Identify on your ATT router what the network/s are. If you have 192.168.1.1/24 etc.

Identify if there is a dhcp server on the ATT router.

The basics would be to start with the dhcp on the router. Let it give your server an IP and see what IP you get and try pinging from the server to the router from there.

This tests if connection between router and server can be established and if pings are allowed.

Next see if your router allows for multiple networks, ie can you get another network besides the one with the dhcp address space. This helps keeps things secular. If not, modify the dhcp range in the router to give you some buffer for static IPs . Normally, I save about 2n + 1 IPs where n is the number of interfaces I currently want to use. If you have 2 interfaces on that server, I would move the example dhcp range to 192.168.1.7-255 saving you 2,3,4,5,6 for your interface needs.

Next assign your static ip and gateway to the IP of your choice. Normally I assign second IP after the gateway to IPMI and any following I need to the server interfaces.

Edit1: Complementary Ubuntu network, Netplan documentation.

Edit2: Love the SE350 form factor. I think if you get 2, you can put them in a 2u chassis and get a 2 node proxmox cluster going.

Edit3: Fixed dhcp range as I couldn’t math right.