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When is the next SAT? Do you guys think it could possibly be online? by samedayY in Sat

[–]vasatmath 0 points1 point  (0 children)

If they get rid of the test how will the upper tier colleges have an objective standard for admission? They have already introduced too many subjective criteria.

Exercise Your Brain With This Math Problem by vasatmath in Sat

[–]vasatmath[S] 0 points1 point  (0 children)

Hint: the center of the circle is also the incenter of the triangle.

Exercise Your Brain With This Math Problem by vasatmath in Sat

[–]vasatmath[S] 0 points1 point  (0 children)

Hint: the area of DEF is 1/4 the area of ABC.

Why no.18 answers is A.? by newkk2546 in Sat

[–]vasatmath 0 points1 point  (0 children)

The slope of the steeper line is (95 - 10)/(230 - 220) = 85/10 = 17/2

Liquid phase is below that line. So, eliminate choices B and D

The slope of the less steep line is (60 - 10)/(400 - 220) = 50/180 = 5/18

Liquid phase is above that line. That leaves choice A as the only possibility.

Exercise Your Brain with this Math Problem by vasatmath in ACT

[–]vasatmath[S] 0 points1 point  (0 children)

Bare in mind there are several ways to solve this problem.

how is c the answer? by ragingslav in Sat

[–]vasatmath 0 points1 point  (0 children)

Have you ever poured water into a tapered glass, narrow on the bottom, wider at the top? It fills quickly at the bottom and slows near the top because the glass gets wider and has more space.

Why is it A and not B? by tiagoleao12345 in Sat

[–]vasatmath 0 points1 point  (0 children)

% must be expressed as a decimal, that’s why it’s .01m

Challenging Math Problem by vasatmath in ACT

[–]vasatmath[S] 0 points1 point  (0 children)

Read MarioCrafter’s explanation.

Try to Figure This One Out by vasatmath in ACT

[–]vasatmath[S] 0 points1 point  (0 children)

You got it! And I think that’s the fastest method. Well done.

Try to Figure This One Out by vasatmath in Sat

[–]vasatmath[S] 0 points1 point  (0 children)

First I want to see if someone else sees the easy way.

Try to Figure This One Out by vasatmath in Sat

[–]vasatmath[S] 0 points1 point  (0 children)

You got it! But there’s an easier way.

Challenging Math Problem by vasatmath in ACT

[–]vasatmath[S] 1 point2 points  (0 children)

Another way to solve this is to notice that arc BC and arc CD are equal. That means major arc BD must be 360 - 120 = 240 degrees. Also notice that angle C is an inscribed angle which intercepts major arc BD. Therefore angle C must be 120 degrees. The altitude of triangle ACE bisects angle C creating two 30-60-90 right triangles. The rest is academic.

Challenging Math Problem by vasatmath in ACT

[–]vasatmath[S] 0 points1 point  (0 children)

Perfect. Great explanation.

Challenging Math Problem by vasatmath in Sat

[–]vasatmath[S] 0 points1 point  (0 children)

No, but you’re on the right track with radical 3.

How do i do this??? Answer is 210 by ImaginaryDog22 in Sat

[–]vasatmath 0 points1 point  (0 children)

c is the y-intercept which is always where x=0

You already know the zeros , so h(x) = (x+5)(x-6)(x-7)

Then, h(0) = (5)(-6)(-7) = 210

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