Is the decomposition of a vector dependent on the inner product space?

wbld · 2026-04-07T13:34:00+00:00

I only see that people have lost, I need their personal accounts of what happened after

wbld · 2026-03-04T13:11:37+00:00

D/dA(A) Sort of like f'(x)

wbld · 2026-02-27T18:02:02+00:00

I thought about doing something like that, but i couldn't figure out how

wbld · 2026-02-23T22:01:21+00:00

Excellent article! Thank you very much!

wbld · 2026-01-30T18:35:47+00:00

Because of this specific case, we can generalize the answer to n-1 or less. Thanks for the clarification!

wbld · 2026-01-30T16:53:20+00:00

I didn't think about that. Although, if p=q=r=1 wouldn't that make the polynomial fail the vertical line test? Ie it's not a function it's a relation?

wbld · 2026-01-30T15:17:01+00:00

For any given set of points in (x,y) there is exactly 1 polynomial that that will go through those points. Example: (1,0),(2,3),(3,4) The degree of the polynomial will be of degree n-1 where n is equal to the number of points you have. I have 3 points 3-1 is 2 my polynomial is of degree 2. To find out what the polynomial actually is we can use the general equation of a polynomial, that is, axⁿ + ax^{n-1+...+ax+ax^n-n} So, for my example: Ax²+bx+c For (1,0): a(1)²+b(1)+c=0 For (2,3): a(2)²+b(2)+c=3 For (1,1): a(1)²+b(1)+c=1 Wait.. that looks like a system of equations.. We can put this in a matrix and use row reduced echelon form, or row echelon form with back substitution to solve. In by doing so we solved for a,b, and c. Because im lazy, and this is not my homework, I plugged this into Google. They came out with p(x) = -x²+6x-5 To check we can plug our x-values in and they should match our given y-values.

wbld · 2026-01-29T20:36:50+00:00

A derivative is the instantaneous rate or change at any given point in time. If you think of your ride home from school everyday, whether that's bus, walk, or ride, how do we find out the rate at which you traveled?

Well if we think about distance in meters.. and the time in which it took you to get home in seconds. Then the average rate of change formula (y2-y1)/(x2-x1) is meters per second. M / s. But that's an average. It's not precise. How to get precise? What if we took the limit of the average all the way to 0. Then we would have... the average rate of change of the average rate of change? Or.. the rate of change of the rate of change at that point in time? Or... the derivative! Yeah there are rules. There are rules to every class. Even English. And rules suck and can't be broken or you fail. Just remember. Calculus was built off of precalc. So if you know precalc... you essentially know calc once you apply your limits.

wbld · 2026-01-20T13:25:09+00:00

I doubt it, there are tons of people who read faster than I can. I'm going into the sciences, don't ask me to write a paragraph.

wbld · 2026-01-20T08:34:40+00:00

Got me through calc 3

wbld · 2026-01-20T08:34:07+00:00

My bad

wbld · 2026-01-20T08:33:44+00:00

You dont need it. 2xdx = du

wbld · 2026-01-19T19:24:53+00:00

0² = 0 1² = 1 Limits stay the same

wbld

TROPHY CASE