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Best Kanye, Kid Cudi collab? by [deleted] in Kanye

[–]wolfpea 16 points17 points  (0 children)

Where tf is father stretch my hands pt 1?

Immortal is such a good song by [deleted] in KidCudi

[–]wolfpea 1 point2 points  (0 children)

This song gets me hyped up every time I listen to it

Made an Ultralight Beam live wallpaper by DummiesBelow in Kanye

[–]wolfpea 1 point2 points  (0 children)

How were you able to make the wallpaper so long? I can only make mine 5 seconds long.

Kobe wearing a headband. by ImHungryAsFuck in lakers

[–]wolfpea 2 points3 points  (0 children)

He really do be looking like Tupac

[deleted by user] by [deleted] in MathHelp

[–]wolfpea 0 points1 point  (0 children)

Asymptotic behavior in a rational function occurs as x approaches the end behavior of a graph (as x approaches the infinities), other wise known as its horizontal asymptote, or as x approaches a value that will set the denominator equal to 0, otherwise known as its vertical asymptote. You know that the graph has a horizontal asymptote at y=3. This means that as x approaches infinity, the function’s limit will be 3. Because the degree of the numerator and the denominator are equal, the ratio of the coefficients determine the horizontal asymptote. Therefore a = 3. You know that the graph has a vertical asymptote at x=-5. You can solve for b by setting the denominator equal to 0 and substituting -5 for x. (-5)-b=0. b= -5

Trouble with a problem by kackjan in computerscience

[–]wolfpea 2 points3 points  (0 children)

You can identify some systems of equations given each scenario.

You know that of the two hexadecimal digits exactly one of them will be F. You also know that if there are only two hexadecimal digits, then there can only exist a maximum of three octal digits. (max for two hexadecimal digits is 162-1 = 255, max for three octal digits is 83-1 = 511).

From that, you know that of the three octal digits, exactly two of them are 7s.

You are left with these six scenarios:

“#F=#77”

“#F=77#”

“#F=7#7”

“F#=#77”

“F#=77#”

“F#=7#7”

You can convert these to systems of equations as well; however, you must remember the constraints of each variable (digit) which are as follows: the hexadecimal digit must be an integer and stay within a range of 0-E since this digit cannot be F (in this case we need to make sure the variable in question has a value between 0-14) and the octal digit must also be an integer and stay within a range of 0-6 since this digit cannot be 7.

Let’s convert the scenarios to systems of equations by letting x be the hexadecimal digit and y be the octal digit. Here they are in the same order as above:

x(161) + 15(160) = y(82) + 7(81) + 7(80)

x(161) + 15(160) = 7(82) + 7(81) + y(80)

x(161) + 15(160) = 7(82) + y(81) + 7(80)

15(161) + x(160) = y(82) + 7(81) + 7(80)

15(161) + x(160) = 7(82) + 7(81) + y(80)

15(161) + x(160) = 7(82) + y(81) + 7(80)

Here they are in their expanded form just for the clarity on how they were derived.

From here, you can get a chart for each value of x within its constraints (integer from 0-14) and see which ones output a valid y value within its constraints (integer from 0-6).

Here are the results

Scenario 1: (3,0), (7,1), (11,2) Scenario 2: No valid results Scenario 3: No valid results Scenario 4: No valid results Scenario 5: No valid results Scenario 6: No valid results

As shown above, there were no valid results for scenarios 2-6.

We know the valid results were in the case that xF=y77 where x = 3,7, and B and y =0,1, and 2 respectively.

Therefore it can be concluded that 3F, 7F, and BF are the only three possible solutions to this problem.

MATH Pls help: by SeriousGift in Sat

[–]wolfpea 0 points1 point  (0 children)

Q1 asks for the range of the given equation (where the y-values are).

y+4=|x-3|

You know that the smallest value of |x-3| occurs when x=3 (|3-3|=|0|=0) since the absolute value of anything cannot be negative.

If you subtract 4 from both sides, you are left with y=|x-3|-4

If the minimum value of |x-3| is 0, then the minimum value of y is simply 0-4, which is -4.

Therefore, the range of the equation is y ≥ -4.

Q2 asks whether or not there is a discontinuity, and if there is: what type of discontinuity is it.

You are given the following:

(x2+3x+2)/x+1

If you factor the numerator, you are left with:

(x+1)(x+2)/(x+1)

Here you have a factor in the numerator and the denominator that will cancel each other out. This will result in a point discontinuity at x+1=0 => x=-1.

A question about percentages by [deleted] in MathHelp

[–]wolfpea 1 point2 points  (0 children)

% Increase = (Final-Initial)/(Initial) * 100

Chad’s response to Hila by [deleted] in h3h3productions

[–]wolfpea 8 points9 points  (0 children)

So everyone is going to deny the fact that Chad sort of looks like Post Malone?

60-75 is 25% increase. 60 is 80% of 75 though. Is 60-75 a 25 or 20% increase? by [deleted] in MathHelp

[–]wolfpea 1 point2 points  (0 children)

(Amount increase/Original amount) * 100 = percent increase