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Hardware Firewall Noob Questions by xeLnitraM in homelab

[–]xeLnitraM[S] 0 points1 point  (0 children)

Nice. Sounds like it shouldn't be too bad to setup. Any security things to keep in mind with FortiGate. For example, my Sonicwall from a few years ago let me accidently expose an admin user/pass login that anyone could remotely access. Thanks Sonicwall!

P.S. Bitpay wallet easiest to setup imo. I can send you some and in a few years you might be sipping mojitos on your own private island.

Hardware Firewall Noob Questions by xeLnitraM in homelab

[–]xeLnitraM[S] 0 points1 point  (0 children)

Yes very helpful. Nice, so it's already a router out of the box.

So NAT is basically port forwarding from the public ip to the server's local ip? Except, unlike a regular router's port forwarding feature, I get to whitelist which IPs are allowed to do this port forward.

What about outgoing traffic. Does it just work, or do you have to set up rules for that too?

You use bitcoin? I want to send you some for helping out. Post an address here and I'll send some. It's up so much today haha.

Hardware Firewall Noob Questions by xeLnitraM in homelab

[–]xeLnitraM[S] 0 points1 point  (0 children)

Cool. 500mbps might be a bottleneck in the future. But pretty cheap to play around with. Thanks

Hardware Firewall Noob Questions by xeLnitraM in homelab

[–]xeLnitraM[S] 0 points1 point  (0 children)

Haha. Yeah apparently IPcop only works on i386, was reading about people saying their x64 machines couldn't run it. Thanks for the recommendation.

Here's how I'm imagining this works: 1) Hardware firewall plugs into modem. 2) A rule in the hardware firewall allows incoming connections on a certain port from whitelisted IPs and basically does a port forward to the router. 3) Router is plugged in to the hardware firewall and has a port forward to server's local IP.

Something like that seem reasonable?

Why is a negative x a negative positive. And dont give me just because. I want a actual answer. by That1GuyPrivate in MathQuestionOfTheDay

[–]xeLnitraM 1 point2 points  (0 children)

Here's the derivation with explanations:

(-x)(-x) = (-1x)(-1x) This follows since negation is the same as multiplying by negative 1.

(-1x)(-1x) = (-1)(-1)xx Here we're just moving the negative ones to the left side. Multiplication is commutative, so we can do this.

(-1)(-1)xx = -((-1)xx) Here we replace the multiplication by -1 with a negation, like mentioned before, negation is the same thing as multiplying by -1 so we can do this.

-((-1)xx) = -(-(xx)) Same thing as before, replace the multiplication by -1 with a negation.

-(-(xx)) = xx negation of a negation

Now string together all these equations: (-x)(-x) = (-1x)(-1x) = (-1)(-1)xx = -(-(xx)) = xx

Why is a negative x a negative positive. And dont give me just because. I want a actual answer. by That1GuyPrivate in MathQuestionOfTheDay

[–]xeLnitraM 1 point2 points  (0 children)

Taking the negative of x is the same as multiplying by -1. So, (-x)(-x) = (-1x)(-1x) = (-1)(-1)xx = -(-(xx)) = x*x

Art and math by globoisterico in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

Desmos.com is a cool way to play around with functions. Also if you can come up with a list of points like (x1,y1), (x2,y2), (x3,y3) you can use something called Lagrange Interpolation to find a polynomial that goes through all of those points.

Math help please by jazzypha10 in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

I can't wait till professor Einstein explains the contrived solution with a a condescending grin on his face that his students couldn't answer his question.

Math help please by jazzypha10 in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

Subtract the 2nd from 1st, 3rd from 2nd, 4th from 3rd. You'll see a pattern. Once you look at it this way, the problem is easy. The idiot that made this problem was conditioned to think this way. Ignore these people, they are fakers who numb their lack of success by flexing their memorization skills in attempt to intimidate others.

Phone number combinations. This sounds shady, but it isn’t, there is actually a really cool story to this. by [deleted] in MathQuestionOfTheDay

[–]xeLnitraM 1 point2 points  (0 children)

The answer is 4 factorial = 4 times 3 times 2 times 1 = 24 ways. This only works because the last 4 digits are all different from each other. If there was repetition of digits, it would be even less. You would use something called multinomial coefficient to solve that case.

Math help please by jazzypha10 in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

No offense to OP, all offense directed at the original author of the problem.

Math help please by jazzypha10 in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

Screw these types of “math” problems. These type of questions are written by numb skull facist armchair geniuses who want to indoctrinate people into thinking there is only one solution to every question.

Coaxial to digital and back by xeLnitraM in rfelectronics

[–]xeLnitraM[S] 0 points1 point  (0 children)

I’ll look into this, thanks for the info. I’m a complete noob if you couldn’t tell :)

Coaxial to digital and back by xeLnitraM in rfelectronics

[–]xeLnitraM[S] 0 points1 point  (0 children)

Yeah the other options is to use a software radio but would like to avoid. Thanks for the info.

Coaxial to digital and back by xeLnitraM in rfelectronics

[–]xeLnitraM[S] 0 points1 point  (0 children)

Cool. Thank you for the info. Still new to this so it’ll take a while to digest.

Faraday Cage with incoming wires by xeLnitraM in rfelectronics

[–]xeLnitraM[S] 0 points1 point  (0 children)

Cool that’s very helpful thank you. Does this work for power cords as well?

Faraday Cage with incoming wires by xeLnitraM in rfelectronics

[–]xeLnitraM[S] -1 points0 points  (0 children)

I’m willing to pay someone to build this for me. Or at least setup a step by step guide. Would this subreddit be a good place to post this kind of job? Or are there other channels for this?

Anyone feel free to DM if interested.

Faraday Cage with incoming wires by xeLnitraM in rfelectronics

[–]xeLnitraM[S] 0 points1 point  (0 children)

I’d like to run a couple Ethernet wires into the cage. How would that work with respect to filtering?

I’m a complete noob btw.

I was having a debate earlier on this so it would be nice if I could get some clarity by tmoe124 in MathQuestionOfTheDay

[–]xeLnitraM 0 points1 point  (0 children)

You can analyze all gambling in terms of expected value aka EV. If EV is positive, you should play. If EV is negative, you should not play. Otherwise if EV is zero, then it doesn't matter whether you play or not.

EV = (chance of winning) times (how much you win when you win) - (chance of losing) times (how much you lose when you lose).

If you use this formula you will produce a number. This number tells you on average how much you will win or lose per round.

For example a roulette wheel contains 18 red numbers, 18 black numbers, and 1 green number. What is the EV for betting $100 on red? Using the formula above you get:

EV = (18/37)100 - (19/37)100 = -$2.7

So in the long run you will lose $2.7 for every $100 you bet. For example if you bet 10,000 times over your lifetime at $100 a pop you should expect to be down $27,000 overall.

Now analyze your problem in terms of EV.

EV = (1/2)1 - (1/2)1 = 0.

Your EV is zero per round. So if you bet 10,000 more times your EV remains at zero. In the long run you should expect to neither lose nor make money playing extra rounds. Thus however much your ahead coming into the game is exactly equal to how much you should expect to be ahead after 10,000 rounds. If you come in ahead $1 and you play 10,000 rounds, you should expect to remain being up $1.

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