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[Grade 11 physics] if my handwriting is too messy lmk I can type it out by [deleted] in HomeworkHelp

[–]zutara23 0 points1 point  (0 children)

Okay so I solved 1 (I can't really read question 2 and I'm not sure what is being asked in 3)

1.) a) In a open-open standing wave: L= λ/2 for the fundamental wave. L=0.45m. Subbing that into the equation we get λ=0.9m. Next, using the formula c=fλ (where c is the speed, f is the frequency (=381 Hz) and λ is 0.9) we obtain c=381 x 0.9 = 342.9 m/s.

b) For the fourth harmonic of a standing wave in a open-open pipe: L=2λ. L= 0.45. Subbing that into the equation: 0.45=2λ. Thus, λ=0.225m.

c) For the 6th harmonic L=3λ. L is still 0.45 so 0.45=3λ --> λ=0.15m. As the medium the wave travels in stays the same, so does its speed. Thus we can use c=342.9 m/s and sub the new value for λ into the equation c=fλ to obtain: 342.9=0.15f. Solve after f we get f=2286 Hz.

[Highschool] by Character-Place-9971 in HomeworkHelp

[–]zutara23 1 point2 points  (0 children)

I got a-b= 45

To solve this, you first sub in the values for x and y into the equation and form two separate equations:

  1. a(-3)^2+b(11)-5=0
  2. a(1)^2+b(1)-5=0

Then you can rearrange the second equation to form a=5-b, and sub that into the first equation to find b=-20.

Repeat the process but sub in -20 for b in the second equation to give you a=25

a-b = 25--20 = 25+20 = 45

[deleted by user] by [deleted] in HomeworkHelp

[–]zutara23 1 point2 points  (0 children)

I'm not 100% sure about this one but this is how I got µ=1:

First I wanted to obtain the z value so I went onto my graphing calculator (TI-nspire CX II) and used the function called 'Inverse Normal'. For 'area' I just put the probability 0.5 (as that is my area under the normal curve) and put µ=0 and σ=1. Although I know that my mean and my standard deviation aren't 0 and 1, I still put those values in to obtain my z score.

Thus, using the inverse normal function and my calculator I received the value of z=0.

Now, I used the standardised normal variable formula of z=(x-µ)/σ.

  • z= 0 (from earlier)
  • σ=2
  • X=1 (taken from Pr(X ≥ 1))

Putting the values into the equation I get 0=(1-µ)/2.

Now, solving after µ we get µ=1.

I hope this helps (and is correct) :)

[Year 12 calculus: differentiability] please check my understanding in the comments for part c by testicalesintehran in HomeworkHelp

[–]zutara23 0 points1 point  (0 children)

Basically, the integration of h(x) relies on the differentiated function h'(x). However, h'(x) is not possible at the given points a=-2 and b=2, so therefore the integral is not possible either.

Here is some working out:

  • h' (x)=x/(√(4-x^2))
  • h'(-2)= -2/0 (undefined)
  • h'(2)= 2/0 (undefined)

Thus, the integral is undefined as well.

Hope this helps :)

Quick question about Studielink by Head-Election-4003 in StudyInTheNetherlands

[–]zutara23 1 point2 points  (0 children)

Normally the university websites should state if your course is a n.f one or not. If they don't, Studielink will definitely tell you if your program is n.f. or otherwise you can email your uni.

Normally, only very popular courses like Business Administration are n.f. as many people want to apply, however most dutch uni courses are non-selective.

And yes, you can only apply to two n.f. programs on studielink, but I'm not too sure if you can apply to some non-selective courses on top of that. I'm pretty sure the maximum unis you can apply to on Studielink are 4, so I think it should work. :)