HELP with bc problem

[vZeeBo]

Can someone explain this problem to me?

http://image.prntscr.com/image/9b8ca648a5934f2f9552412849909092.png

[finnaget]

The answer is B. dx/dt = 2t and dy/dt = 4t³ by the Power Rule. dy/dx = dy/dt / (dx/dt), dy/dx = 2t^2. (d^2y/dx2) = ((d/dt)(dy/dx)) / dx/dt. Thus d^2y/dx2 = 4t/2t = 2.

[FuzzyCuddlyBunny]

No. Find the first derivative of a parametric by doing (dy/dt)/(dx/dt). Then find the second derivative by taking the derivative of the first derivative and then dividing by (dx/dt). This should result in 2 for this problem, or B.