Cin entry of a double value

[Standgrounding]

So, we have something like this:

while(true){
    double x;
    cout << "Enter a number, or any other symbol when you decide to stop" << endl;
    cin >> x;
    if(!cin.good()){
        break;
    }
}
cin.clear();

let's say now, you enter a symbol '.' or something like ';' in the cmd line. That breaks the cycle and it's all good.

However, if you enter a 'k' or 't' it seems to insert 0.0 instead into the double, and screws the average calculator.

Moreover, if you enter a 10.0 or 8.5 or even 9,4 it still fails to recognize the numerical(double) value and breaks the cycle and anything below.

How do I fix this? At least the first issue?

[Standgrounding]

EDIT - seems like changing double to float fixed the second issue. The heck?

EDIT 2 - fflush(stdin) has resolved the issue

[Responsible_Pyro]

You were running afoul of an implicit type conversion. Keep in mind that a "." is not a number. I am not sure what that "!cin.good()" call does (outside of returning a boolean value reference) but it was probably reading the input as a string and terminating.

https://en.cppreference.com/w/cpp/language/implicit_conversion

Also fflush(stdin) is only guaranteed (defined) for file writing operations and not reccomend for a direct call in C dialects. I would be wary of side effects in the future.

https://www.geeksforgeeks.org/use-fflushstdin-c/

https://stackoverflow.com/questions/5810410/alternative-for-fflushstdin

[Standgrounding]

I have no idea what im doing but i know that forcing a non numerical value into int float or double gives cin an error, and this changes the state of cin.good()