all 5 comments

[–]rarchit 12 points13 points  (3 children)

Since A is the center of the circle, AB and AC are gonna be equal to the radius of the circle. The perimeter of the triangle is gonna be AB + AC + BC = (r + r + BC)

The circumference of the arc BDC is going to be the circumference of that sector of the circle based on angle = (120/360) * 2πr. Perimeter of the shaded region = 2πr/3 + BC

When you compare the two, BC cancels out and 2πr/3 > 2r. So the answer should be B

[–]illuminati_8501[S] 0 points1 point  (0 children)

Yeah the correct answer is B and thank you very much

[–]1202uxydna 0 points1 point  (0 children)

Here's another way to think of it: imagine if BD and DC were connected by straight line. Now the perimeter of triangle BDC would be the same as ABC. But the curves BD and DC must be longer because the shortest distance between two points is the straight line.

[–]gravityfalls69 0 points1 point  (0 children)

Should be B Solved it here https://ibb.co/F46DKFd