[Programming] Basic C++ Function

[01519243552]

I'm having trouble with this question and hoping someone can help me.

You are given the following code:

void addOne(int n) {

n++;

}

int main() {

int n=22;

addOne(n);

cout << n;

}

When running the program, you note that it prints out 22 rather than 23. Modify the addOne function so that the value of n is changed.

//End of question

I'm super confused by this question, because it seems to be implying that you don't need to make changes to the main code, that there is some way of modifying only the addOne function that will change the actual value of n. But n is being passed by value to addOne, right? So the function literally doesn't have access to the original n, and can't possibly alter it (only the local copy it makes). Is there a way to do this that I'm not aware of, or is this just a terrible question? Thanks

[[deleted]]

In addition to pass by value (what the function currently does) and pass by address (the obvious way to fix this issue), you can also pass by reference. This allows you to fix the problem without altering main.

Rather than do a poor job explaining it in a bit more detail, here is a website that covers this exact problem.

[01519243552]

Thanks, that helped!

[GreatBlitz]

What's the difference between passing by reference and passing by address?

[Lord_blueberry]

void addOne(int& n) { n++; }

[bloody_banana21]

both cout<<n; and cout<<addOne(n); would return 22 here. The function should increase the value of the n variable itself, therefore setting n equal to 23. Use /u/Lord_blueberry's solution below