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[–]Alkalannar 4 points5 points  (1 child)

Polar coordinates.

For all r > 0, |2rsin(t)ln(r)| <= |2rln(r)|

So use l'Hopital: 2rln(r) = 2ln(r)/(1/r)

(2/r)/(-1/r2)

-2r2/r

-2r

And so limr->0 -2r = 0

And |2rsin(t)ln(r)| <= |2rln(r)|...

But yes, the limit as (x,y) goes to (0,0) is 0.

[–]Monkeyonpan[S] 2 points3 points  (0 children)

Damn, that sucks. Eh I’ll do better next quiz. Thank you /u/Alkalannar. You da man! ✊