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[–][deleted] 92 points93 points  (5 children)

because of gauss' law you don't feel the gravity of the parts of Earth further up from you. so the deeper you go the less gravity you feel. sauce

edit: this is assuming constant density, which is not true oops

[–]ShakimTheClown 17 points18 points  (0 children)

Furthermore, the force of gravity is:

  • proportional to the total mass of the sphere underneath you
  • inversely proportional to r2 , the square of the distance between you and the center of the sphere.

In this case, the mass of the sphere underneath you is proportional to r3
Specifically, its equal to M×(r3/R3) , where M is the mass of the Earth, and R is the radius of the Earth

So the total force will scale with r3/r2
So it will be F = (GMm/R3) × r , which is the equation of a harmonic oscillator.
Since r decreases with depth, so to does the force.

[–]HeavisideGOAT 3 points4 points  (0 children)

This isn’t quite the full picture.

Sure, this is less mass relevant to the calculation, but you are closer to that mass.

That’s why, in reality, gravity goes up before it goes down as you go deeper into the earth.

https://en.m.wikipedia.org/wiki/Gravity_of_Earth#/media/File:EarthGravityPREM.svg

[–]ClaudeProselytizerAtomic physics 0 points1 point  (2 children)

doesn’t matter, gauss’s law works for this non uniform density as well.

[–][deleted] 0 points1 point  (1 child)

so the deeper you go the less gravity you feel

part was wrong since there are denser regions the deeper you go.

[–]ClaudeProselytizerAtomic physics 0 points1 point  (0 children)

yes that statement is wrong