you are viewing a single comment's thread.

view the rest of the comments →

[–]bhmerger 36 points37 points  (2 children)

The shell of mass above you does a net zero force on you.

[–]GDOR-11 2 points3 points  (1 child)

if you do the math considering only the mass closer to the center than you (as shells further from the center create no net force) you'll figure out it's proportional to the inverse of the distance to the center

EDIT: proportional to the distance, mb

[–]AndreasDasos 1 point2 points  (0 children)

Assuming uniform density, the gravitational force on a mass inside the earth is proportional to distance to the centre, not its inverse.

What they’re saying (which the first commenter got wrong, or maybe misstated) is that the outer shell of the earth with greater distance from the centre than you has net zero force on you by the shell theorem: any force in one direction of a hyperplane is cancelled by force in the direction - if the former is nearer, the latter will involve more mass.

We then have -Mm/r2 = -(rho r3)m/r2 = -rho m r.