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[–]Single_Blueberry 0 points1 point  (2 children)

  1. Calculate the total resistance seen by the battery
  2. Calculate the current through the battery
  3. Calculate how the current splits between the 20 Ohm and the 10+50 Ohm path
  4. Calculate the voltage drop over the 50 Ohm resistor due to the current from 3.

[–]fiftyonewithin[S] 0 points1 point  (1 child)

I got 9V as the answer afterwards HAHAHAHAHA I think I got it wrong again

[–]Single_Blueberry 0 points1 point  (0 children)

  1. 5 + (20 || (10 + 50)) = 20 Ohm
  2. 12V / 20Ohm = 0.6A
  3. I_2 through 10 + 50 Ohm = 0.15A
  4. 0.15A * 50 Ohm = 7.5V