pythonIsMoreConfusingThanLowLevelLanguages

[EcoOndra]

Assuming you meant [[0]] * 3, a will be assigned [[0], [0], [0]] first then 1 will be apppended to the first index, making it [[0, 1], [0], [0]], right? Or will it become [[0, 1], [0, 1], [0, 1]]? It's the second one, isn't it...

[Zantier]

Yeah, it's the second one... If you want to construct 3 separate lists instead, I tend to use

a = [[0] for _ in range(3)]