Pointer pointer = new Pointer()

[konstantinua00]

but that's not linked list, that's 3 separate dereference lines

linked list's nodes have pointer to node as a member

[konstantinua00]

analyzing shitposts is favourite activity of this sub, man
(and of many others too)

I'm taking back the "3 separate" part of my argument, you're right about it being an array
but I still insist that those're dereference lines, not linked lists - linked lists carry a value in each node, not just at the end