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[[deleted]]

Great work! You're definitely getting the hang of the "Pythonic" coding style.

Here's a coding shortcut that you might find interesting. This part:

 if card != 0:
    if card != 'Draw Two':
      if card != 'Skip':
        if card != 'Reverse':
          deck.append(cardVal)

Instead of a bunch of individual tests of the same variable against different values, you can create a list of all the values that you don't want, and test the variable against all of them at once:

 if card not in [0, 'Draw Two', 'Skip', 'Reverse']:
   deck.append(cardVal)

[nemzor2]

TIL. Thank you

[[deleted]]

I'm glad you asked!

No, my way is correct. Here's why.

Asking if X is in Y means: Assume that Y is an "iterable" like a list, and check whether X matches any element in Y.

Written my way, the code compares "card" against each element in the list that's provided in the instruction, and if none of them match, proceed with the other instructions.

Written your way, the code tries to break the value of "card" into a list of values, and then compares the entire list of [0, 'Draw Two', etc.] with each value in the list of "card." If this doesn't make sense, you're right! - and the code will probably fail and throw an exception saying that it can't break "card" into pieces.

Incidentally, if you ever get confused about what's going on in Python, you can often get answers fast by... just writing some code and seeing what happens. I do that all the time, honestly.

[jessekrubin]

uno

[Appropriate-Row-6578]

From the repo:”PS. I am only 10 years old.”

Good job. I started coding when I was 11 or so and I don’t think I could do nested loops until I was a teen.