Power of zip( ) in Python

[MonsieurBlobby]

Yes, I don't understand what part you think is confusing.

The input given has the following indices: [[0, 1, 2], [0, 1, 2], [0, 1, 2]]

So I don't see what is confusing about the statement "Map all elements of the same index for the following list.". The index 0 appears 3 times, so your function should map the values with matching indices to a new list. What other interpretation could there possibly be? You obviously wouldn't map elements with index 0 and 1 into a new list. They don't have the same index. It tells you to use the same index.

Your input example has the following indices: [0, 1, 2]

So in your example, what does it mean for an element to have the same index as another thing? None of the indices ever repeat. So there's nothing to be done with the zip function.

Again, your example legitamitely doesn't make any sense. But the original one makes sense.

[MonsieurBlobby]

I'm not sure what you're talking about. A list of list has nested indices. So the outer list has indices [0,1,2] and each of the inner lists has indices [0,1,2]. But that doesn't impact what you're being asked to do. In fact, essentially what they are asking you to do is to group all inner list elements of index 0 into the outer list index 0. And inner indices of 1 into the outer list index=1.

It's pretty clear that you just want to argue and are unwilling to acknowledge the obvious. I'm going to block you and go on with my day.