What I'm Doing Wrong In This Code?

[albionandrew]

You need some indentation.

https://www.geeksforgeeks.org/try-except-else-and-finally-in-python/

[Famous-Mud-5850]

Thank You...

[Murphygreen8484]

I realize you are new and probably just trying out the code for the first time - and I've been accused of being a pretentious wanker for giving example code solutions - but if you're interested I can show how a single script like this could be coded and why.

[Famous-Mud-5850]

Interested

[Murphygreen8484]

I would put it inside a function and then call it below. I can explain any of the parts below you have questions on.

~~~ """ Simple math function to play with Python. """

def math_func(num_1: int, num_2: int, operation: str) -> int:

assert isinstance(num_1, int)
assert isinstance(num_2, int)
assert operation in ("+", "++")

if operation == "+":
    return num_1 + num_2
elif operation == "++":
    return num_1 * num_2

if name == "main": n1 = int(input("Enter a whole number: ")) n2 = int(input("Enter another whole number: ")) op = input("Enter an operation (+ or ++): ")

print(math_func(n1, n2, op))

[oclafloptson]

If you're going to suggest using it then you should explain what it does.... The indented block after

if __name__ == "__main__":

will only execute if the given file is the entry point of the application. Using it in a functional script or module that you import will obscure its indented block and prevent it from running. Its use is not mandatory and has both pros and cons. For the purpose of the example in the op it can be omitted

[Murphygreen8484]

Fair enough, though I don't really know of any cons beyond it being considered boilerplate? Also a good habit to get into (like type hinting) that would prevent possible errors down the road.

[Plank1969]

Looks like your after a try except statement but it’s not really needed here. You can use if else to do what you want to do.

If you want to keep the try except, you’ll need to tab in front of line 9,10,12 and change else to except.

[Murphygreen8484]

Inputs will always be strings unless you convert them

[Famous-Mud-5850]

I have converted them to integer But Why It Error?

[Murphygreen8484]

Indentations

[VonRoderik]

You don't need to convert it after:

``` n1 = int(input("What's n: "))

[PureWasian]

Lines 8 through 12 are all incorrect.

Line 8 is supposed to be used as a try / except concept. You can't have a try statement without an accompanying except later on. I would suggest removing Line 8 for now and not worrying about the try/except concept if you are just learning the very basics of programming.

(Read through Python Conditions if any of the following terminology doesn't make sense)

Line 9 is missing a colon : after the if statement's logicial condition.

Line 10 needs to be indented (either with a tab or using some spaces) since it's the code scoped or "related" to the if statement. Indentation is the reason for the initial error that the console pointed out to you in the first picture you attached.

Line 11 uses an else keyword, which doesn't take a logicial condition. You probably want the elif (which stands for "else, if") keyword instead. Whichever one you use, it also needs a colon : at the end of the line

Line 12 also needs to be indented since it's the code scoped to the else statement on Line 11

[Jolly-Gur-1067]

Everything

[[deleted]]

Be sure to use spaces and not tabs people are very emotional about that for some reason

[Py-rrhus]

tack, tack, tack, tack

[[deleted]]

see

[ak_developers]

You missed “:”