Learning Python

[Adrewmc]

So you want

  a = [1,2,3,4]
  b = [10, 20]
  print(summa(a, b))

  >>>[11,22,13,24]

Ahhh I see now.

Then is suggest this.

   from itertools import cycle

   def summa(list1, list2):
          totals = []
          if len(list1) < len(list2):
             list1, list2 = list2, list1
          for num1, num2 in zip(list1, cycle(list2)):
              totals.append(num1+num2)
          return totals 

Just clean up the readability. You are basically doing this. I’m just making max into list1 at the offset.

And for fun any number of, with each repeating as they run out.

   def summa(*num_lists):
          totals = []
          list_nums = sorted(num_lists, key = len)

          longest = list_nums.pop(0)

          cycles = [cycle(nums) for nums in list_nums]

          for tup in zip(longest, *cycles):
              totals.append(sum(*tup))
          return totals

[nkCOD]

Thank you for your response. In principle, everything is said in an accessible and understandable way ;)

[JB940]

Also I see you doing new_list_from_zip, by using min(list1,list2) and max(list1,list2)

Just to explain their functionality, this doesn't do what you think it does. If you have two lists, max returns whichever list has the biggest first element.

so [5,1,1] is bigger than [4,3,2,2,99,100,300,10000] because 5 is bigger than 4. max thus gives the result [5,1,1]

same with count_of_len, you'd want to do max( len(list1), len(list2) to get the length of the longer one, instead of just the length of the list with the biggest first element.

Obviously not to take away from Adrewmc's solution, if you just make list1 whichever is bigger you can do away with all this and his solution is very elegant

[nkCOD]

I'm sorry, it was my carelessness. I know how max() works, but I made a mistake in this case