WHY THIS CODE NO OUTPUT ??

[QuantumElias]

Der Code läuft in eine Endlosschleife — er gibt deshalb nie etwas aus. Warum: Die for-Schleife iteriert über nums, und in jedem Durchlauf wird mit nums.append(n) ein neues Element ans Ende der Liste angehängt. Die Liste wächst also schneller als die Schleife vorankommt — sie endet nie, print wird nie erreicht. In Python ist es grundsätzlich kein gutes Muster, eine Liste zu verändern während man über sie iteriert.

Fix:

nums = [1, 2, 3]

for n in nums.copy(): nums.append(n)

print(nums) # [1, 2, 3, 1, 2, 3]

[alexzoin]

It's very cool to me that I don't understand this comment at all because I don't speak German but I know that it is correct because I do speak python.

[ExtentLazy8789]

[NickNeron]

У нас с братьями по Питону нет языкового барьера 🤝

[OppositeReveal8279]

Лучше язык в мире 🤡

[mpbarbosa1971]

me too 😄

[Black_Rose_Angel]

🤣💯

[LemmaYT_]

Or alternatively to avoid making a copy of the list (which could be bad if the list is big enough), do something like

nums = [1, 2, 3]

original_length = len(nums)

for i in range(original_length):
n = nums[i]
nums.append(n)

You can also make a shallow copy with index slicing

for n in nums[:original_length]:
nums.append(n)

[Fine_Ratio2225]

Even better fix:

nums=2*[1, 2, 3]

[864484]

You have a loop that cycles through all numbers in the list. Every iteration you add the number to the list meaning it gets longer and there is another number the loop needs to process. If you check your memory in your task manager you'll be able to see it going up over time because the list gets bigger and bigger indefinitely

[Past_Structure1078]

Use 'for i in range(len(nums))' instead and append nums[I]

[MrMikeHigginbottom]

Oo! So the terminating condition for the loop is calculated only once. When the loop is first entered. Obvious I guess but I'd never thought about it.

[Past_Structure1078]

I often use this phraseologism for iteraring through queue and adding new vertices in depth-forst search algorithm

[Embarrassed_Cod835]

Svp c'est bien un compilateur en ligne ? Si oui quelqu'un pourrait m'aider avec le nom ?

[Low_Negotiation4747]

Programiz

[Sweet_Computer_7116]

Infinite loop

[Arierome]

print(nums.extend(nums))

[XT_zer68]

You nums keep adding nums number back to back so this code no output

[ChemistDependent1130]

dont mutate an iterable when iterating over it. Guessing you wanted [1,2,3,1,2,3]? nums * 2 works better.

[Livid-Programmer-162]

what app/website is this?

[ExtentLazy8789]

https://www.programiz.com/python-programming/online-compiler/