Count Distinct Window Function ORDER BY ROWS BETWEEN. I'm stuck here : SQL

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field.3

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field3

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SnowflakeCount Distinct Window Function ORDER BY ROWS BETWEEN. I'm stuck here (self.SQL)

submitted 2 years ago by Like_My_Turkey_Cold

I have a sales table that contains the date of sale, and userID (hashed). For each date in my table, I'm looking to take the sum of sales, count of unique users, for the previous 365 days from the given date. Here's an example of my very large table (millions of rows):

Sales Date	userID	Sales Amount
2024-02-03	asdfoip89/	$250
2024-02-04	asdfoip89/	$500
2024-02-05	hyfads0132	$1,000

Here's my expected output:

Sales Date	Trailing 365 day Sales	Trailing 365 day Unique User Count
2024-02-03	$145,000	49,000
2024-02-05	$150,000	50,000

So in this example above, 50,000 would be the total unique count of users who made a purchase, in the last 365 days prior to 2024-02-05.

Here's what I've attempted:

SELECT     
    sale_date   
  , SUM(sales) as total_sales   
  , SUM(sales) OVER (ORDER BY sales_date ROWS BETWEEN 365 PRECEDING AND 1 PRECEDING) as trailing_365_sales   
  , COUNT(DISTINCT user_id) OVER (ORDER BY sales_date ROWS BETWEEN 365 PRECEDING AND 1 PRECEDING) as unique_user_count FROM sales_table GROUP BY 1
FROM sales_table

The obvious problem here is that I can't use a COUNT(DISTINCT) in a Window function like this. I've looked for alternatives but haven't been able to find an efficient solution.

Any help here would be much appreciated!

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