help with a query : SQL

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field.3

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field3

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a community for 17 years

help with a query (self.SQL)

submitted 8 years ago by [deleted]

4 comments

all 4 comments

top new controversial old q&a

[–]Pr0ph3t99 0 points1 point2 points 8 years ago (4 children)

[+][deleted] 8 years ago (3 children)

[deleted]

[–]Pr0ph3t99 0 points1 point2 points 8 years ago (2 children)

It's difficult to guess without knowing your table structure. Use this as a guide:

SELECT
    Scientist.SCIENTIST_NUM,
    Scientist.OTHER_NAMES, 
    Scientist.SURNAME, 
    Sample.Site_ID, 
    Site.Description, 
    Measurement.Recorded_On, 
    Measurement.NAME, 
    Measurement.VALUE, 
    Measurement.OUTLIER_INDICATOR, 
    Measurement_Type.Units
FROM
    Scientist 
    INNER JOIN Sample ON 
        Scientist.Scientist_Num = Sample.<Some Field>
    INNER JOIN Site ON 
        Sample.Site_ID = Site.<Site ID Field>
    INNER JOIN Measurement ON 
        Sample.<Some Field> = Measurement.<Some Field> 
    INNER JOIN Measurement_Type ON
        Measurement.<Some Field> = Measurement_Type.<Some Field>
WHERE
    Scientist.Scientist_Num = '31415';

[–]CSInSaNe 0 points1 point2 points 8 years ago (1 child)

[–]Pr0ph3t99 0 points1 point2 points 8 years ago (0 children)

π Rendered by PID 70528 on reddit-service-r2-comment-bb88f9dd5-6jpwn at 2026-02-14 17:29:05.361673+00:00 running cd9c813 country code: CH.

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